Use the formula in terms of half life from the normal exponential functions
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N(t) = N(0) (1/2) ^ (t/thalf) </span>
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N(0) is the original quantity </span>
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N(t) = quantity remaining at time t </span>
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t is the time </span>
<span>
thalf is half life </span>
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1/16 = (1/2)^(t/3.82) </span>
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16 = 2^(t/3.82) </span>
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4 = t/3.82 </span>
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t = 15.28 days
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6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O
Explanation:
Given equation;
NaC₂H₃O₂ + Fe₂O₃ → Fe(C₂H₃O₂)₃ + Na₂O
To find the coefficient that will balance this we equation, let us set up simple mathematical algebraic expressions that we can readily solve.
Let us have at the back of our mind that, in every chemical reaction, the number of atom is usually conserved.
aNaC₂H₃O₂ + bFe₂O₃ → cFe(C₂H₃O₂)₃ + dNa₂O
a, b, c and d are the coefficients that will balance the equation.
conserving Na; a = 2d
C: 2a = 6c
H: 3a = 9c
O; 2a + 3b = 6c + d
Fe: 2b = c
let a = 1
solving:
2a = 6c
2(1) = 6c
c = 
2b = c
b =
= 
d = 2a + 3b - 6c = 2(1 ) + (3 x
) - (6 x
) = 
Now multiply through by 6
a = 6, b = 1, c = 2 and d = 3
6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O
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Balanced equation brainly.com/question/9325293
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By Tri chlorination, three chlorine atoms can replace the 3 hydrogen atoms in propane molecule to give tri-chlorinated products according to the attached picture.
Here is your answer
Since, carbon atoms are triple bonded.
So functional group present in the compound is ALKYNE
HOPE IT IS USEFUL
There are approximately 160 grams in 1 mol of fe203 molecules therefore there would be 79/160 = 0.49375 mols of fe203 molecules in 79 grams therefore 5 atoms in total for each molecule of fe203 therefore 79/160 *5 =79/32=2.46875 mols in atoms