All categories

3 years ago

Solve for x. 18x−5<−8 or 7x−4≥38

Mathematics

1 answer:

lys-0071 [83]3 years ago

3 0

Answer:

in the first equation: x < -1/6

in the second equation: x≥6

Step-by-step explanation:

just ask!

hope this helps :)

You might be interested in

Write the equation Help!!!

Dmitrij [34]

y = mx + b

where m is the slope and b is the y-intercept.

Here, the slope is -3/2 and the y-intercept is 5.

y = -3/2x + 5

3 0

2 years ago

Read 2 more answers

Xyz^(2) if x=2 y=7 and z=-4

Afina-wow [57]

Answer:

-224

Step-by-step explanation:

xyz^2

(2)(7)(-4)^2

14 x -16

-224

8 0

3 years ago

Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.

SashulF [63]

ANSWER

${r}^{2} = 4 \cos2\theta$

EXPLANATION

The Cartesian equation is

${( {x}^{2} + {y}^{2} )}^{2} = 4( {x}^{2} - {y}^{2} )$

We substitute

$x = r \cos( \theta)$

$y = r \sin( \theta)$

and

${x}^{2} + {y}^{2} = {r}^{2}$

This implies that

${( {r}^{2} )}^{2} = 4(( { r \cos\theta) }^{2} - {(r \sin\theta) }^{2} )$

Let us evaluate the exponents to get:

${r}^{4} = 4({ {r}^{2} \cos^{2}\theta } - {r}^{2} \sin^{2}\theta)$

Factor the RHS to get:

${r}^{4} = 4{r}^{2} ({ \cos^{2}\theta } - \sin^{2}\theta)$

Divide through by r²

${r}^{2} = 4 ({ \cos^{2}\theta } - \sin^{2}\theta)$

Apply the double angle identity

$\cos^{2}\theta -\sin^{2}\theta= \cos(2 \theta)$

The polar equation then becomes:

${r}^{2} = 4 \cos2\theta$

7 0

3 years ago

Beth won 45 lollipops. She gave away some and now she has 28 remaining. How many did she give away?

lapo4ka [179]

Just subtract 45 - 28 = 17 lollipops

Hope this helps!!!

4 0

4 years ago

Read 2 more answers

Evaluate the function found in the previous step at X =-3

babunello [35]

$x-5y=-4x-2y$

In order to evaluate the given function at x = -3, simply replace "x" in the function with -3 and solve.

$-3-5y=-4(-3)-2y$

Multiply -4 and -3 in the function above.

$-3-5y=12-2y$

Add 3 on both sides of the equation.

$-3-5y+3=12-2y+3$ $-5y=15-2y$

Add 2y on both sides of the equation.

$-5y+2y=15-2y+2y$ $-3y=15$

Divide both sides of the equation by -3.

$\frac{-3y}{-3}=\frac{15}{-3}$ $y=-5$

Therefore, at x = -3, the value of y = -5. Hence, f(-3) = -5.

Answer:

f(-3) = -5

7 0

1 year ago