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2 years ago

Are you chemistry because you just blew up my heart

Chemistry

2 answers:

Ratling [72]2 years ago

7 0

Lol cool I guess......

Len [333]2 years ago

3 0

Answer:

i needed that lol

thank you

Explanation:

You might be interested in

Potassium cyanide is a toxic substance, and the median lethal dose depends on the mass of the person or animal that ingests it.

Artemon [7]

Answer:

88,7 mL of solution

Explanation:

Molarity (Represented as M) is an unit of chemical concentration that is defined as the ratio between moles of solute per liters of solution, that is:

Molarity = moles of solute / Liters of solution

If molarity of KCN solution is 0,0820M and moles of KCN are 7,27x10⁻³ moles:

0,0820M = 7,27x10⁻³ moles / Liters of solution

Liters of solution = 0,0887L = <em>88,7 mL of solution</em>

I hope it helps!

4 0

3 years ago

Use the chemical equation below to determine how many moles of ammonia

anzhelika [568]

Answer:

If we assume that there will be enough Hydrogen for the reaction to occur, then there will be 8 moles of NH

Explanation:

The balanced equation will look like this:

4N2 + 4H2 -> 8NH

6 0

3 years ago

Given the following heats of combustion. CH3OH(l) + 3/2 O2(g) CO2(g) + 2 H2O(l) ΔH°rxn = -726.4 kJ C(graphite) + O2(g) CO2(g) ΔH

sergeinik [125]

Answer:

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

Explanation:

The formation reaction of CH_3OH will be,

$C(s)+2H_2(g)+\frac{1}{2}O_2\rightarrow CH_3OH(g),\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

$C(graphite)+O_2(g)\rightarrow CO_2(g), \Delta H_1=-393.5kJ/mole$ ..[1]

$H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l), \Delta H_2=-285.8kJ/mole$ ..[2]

$CH_3OH(g)+\frac{3}{2}O_2(g)\rightarrow CO_2(g)+2H_2O(l) , \Delta H_3=-726.4kJ/mole$ ..[3]

Now we will reverse the reaction 3, multiply reaction 2 by 2 then adding all the equations, Using Hess's law:

We get :

$C(graphite)+O_2(g)\rightarrow CO_2(g) , \Delta H_1=-393.5kJ/mole$ ..[1]

$2H_2(g)+2O_2(g)\rightarrow 2H_2O(l) ,\Delta H_2=2\times (-285.8kJ/mole)=-571.6kJ/mol$ ..[2]

$CO_2(g)+2H_2O(l)\rightarrow CH_3OH(g)+\frac{3}{2}O_2(g) ,\Delta H_3=726.4kJ/mole$ [3]

The expression for enthalpy of formation of $C_2H_4$ will be,

$\Delta H_{formation}=\Delta H_1+2\times \Delta H_2+\Delta H_3$

$\Delta H=(-393.5kJ/mole)+(-571.6kJ/mole)+(726.4kJ/mole)$

$\Delta H=-238.7kJ/mole$

The standard enthalpy of formation of methanol is, -238.7 kJ/mole

4 0

2 years ago

What is the length in inches (in) of a 100-meter soccer field?

max2010maxim [7]

Answer:

3937 inches

Explanation:

1m = 39.37 inches.

However, we want to know how long a 100m soccer field is, so we have to times the value for 1m by 100.

Therefore, an 100m soccer field = 100 x 39.37 = 3937 inches

7 0

3 years ago

a chemist measured 75.00g of HCL into a volumetric flask and added water until the volume was 1.000 L. what is the molarity of t

Aleks04 [339]

Answer: M = 2.08 M

Explanation: Molarity is expressed as the number of moles per unit volume in liters. First convert the mass of HCl to moles using its molar mass. Then substitute the variables to the formula for molarity.

75.00 g HCl x 1 mole HCl / 36 g HCl

= 2.08 moles HCl

For Molarity.

M = n / L

= 2.08 moles HCl / 1.000 L

= 2.08 M

6 0

3 years ago