Question

a box measures 4 units by 2 1/2 units by 1 1/2 units. What is the greatest numberof cubes with a side length of 1/2 unit that canbe packed inside the box?

Answer 1

$\frac{4}{\frac{1}{2}}*\frac{2\frac{1}{2}}{\frac{1}{2}}*\frac{1\frac{1}{2}}{\frac{1}{2}}\\\frac{4(2)}{1}*\frac{\frac{5}{2}}{\frac{1}{2}}*\frac{\frac{3}{2}}{\frac{1}{2}}\\\frac{8}{1}*\frac{5}{1}*\frac{3}{1}\\120$