1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vedmedyk [2.9K]
2 years ago
14

¿Cómo se expresaban, en los lienzos o en los papeles de pintar,

Chemistry
1 answer:
elena55 [62]2 years ago
8 0
Can you translate? Please.
You might be interested in
Using a chemical equation to find moles of product from moles...
kaheart [24]

Answer: 0.600 moles

Balanced eqn for decomposition of the rocket fuel:

2 NH4ClO4 (s) ----> N2 (g) + Cl2 (g) + 2 O2 (g) + 4 H2O (g)

Since, 2 moles of NH4ClO4 produces 2 moles of O2 gas, this means that 0.6 moles of NH4ClO4 will produce 0.6 moles of O2 gas

7 0
1 year ago
Difference between Physical and chemical changes <br> At least six examples for each type of change
Tju [1.3M]
Physical<span> changes involve a new </span>form<span> or shape of matter, 
</span>

Chemical change<span> is any </span>change<span> that results in the formation of new </span>chemical<span> substances.</span>
4 0
3 years ago
Read 2 more answers
Give two example for desert plants and animals?<br><br><br><br><br>please mark as brainliest​
aev [14]

Answer:

Plants : Cactus, tumbleweed

Animals : camel, fennec fox

8 0
3 years ago
Read 2 more answers
Please help!! ASAP Calculate the pH of the solution after the addition of the following amounts of 0.0574 M HNO3 to a 80.0 ml so
alexira [117]

Answer:

a) 10.457.

b) 9.32.

c) 8.04.

d) 6.58.

e) 4.76.

f) 2.87.

Explanation:

  • Aziridine is an organic compounds containing the aziridine functional group, a three-membered heterocycle with one amine group (-NH-) and two methylene bridges (-CH2-). The parent compound is aziridine (or ethylene imine), with molecular formula C2H5N.
  • Aziridine has a basic character.
  • It has pKa = 8.04.
  • So, pKb = 14 – 8.04 = 5.96
  • Kb = 1.1 x 10⁻⁶.
  • If we denote Aziridine the symbol (Az),  It is dissociated in water as:

Az + H₂O → AzH⁺ + OH⁻

<u><em>a) 0.00 ml of HNO₃: </em></u>

There is only Az,

[OH⁻] = √(Kb.C)

Kb = 1.1 x 10⁻⁶. & C = 0.0750 M.

[OH⁻] = √(1.1 x 10⁻⁶)(0.075) = 2.867 x 10⁻⁴.

∵ pOH = - log[OH-] = - log (2.867 x 10⁻⁴) = 3.542.

∴ pH = 14 – pOH = 14 – 3.542 = 10.457.

<u><em>b) 5.27 ml of HNO₃</em></u>

  • To solve this point, we compare the no. of millimoles of acid (HNO₃) and the base (Az).
  • No. of millimoles of Az before addition of HNO₃ = (0.0750 mmol/ml) × (80.0 ml) = 6.00 mmol.
  • No. of millimoles of HNO₃, H⁺ = (MV) = (0.0574 mmol/ml) × (5.27 ml) = 0.302 mmol.
  • The no. of millimoles of the base Az (6.0 mmol) is higher than that of the acid HNO₃ (0.302).
  • This will form a basic buffer in the presence of weak base (Az).

<em>pOH = pKb + log[salt]/[base] </em>

  • [salt] = no. of millimoles of the limiting reactant HNO₃ / total volume = (0.302) / (85.27) = 3.54 x 10⁻³ M.
  • [base] = (no. of millimoles of Az – no. of millimoles of HNO₃) / total volume = (6.00 mmol - 0.302 mmol) / (85.27 ml) = 0.0668 M.
  • pOH = pKb + log[salt]/[base] = 5.96 + log[3.54 x 10⁻³]/[ 0.0668 M] = 4.68.
  • <em>pH = 14 – pOH = 14 – 4.68 = 9.32. </em>

<em />

<em><u>c) Volume of HNO₃ equal to half the equivalence point volume :</u></em>

  • At half equivalence point, the concentration of the salt formed is equal to the concentration of the remaining base (aziridine), [salt] = [base].
  • pOH = pKb + log[salt]/[base] = 5.96 + log[1.0] = 5.96.
  • pH = 14 – pOH = 14 – 5.96 = 8.04.

<u><em>d) 101 ml of HNO₃: </em></u>

  • To solve this point, we compare the no. of millimoles of acid (HNO₃) and the base (Az).
  • No. of millimoles of Az before addition of HNO₃ = (0.0750 mmol/ml) × (80.0 ml) = 6.00 mmol.
  • No. of millimoles of HNO₃, H⁺ = (MV) = (0.0574 mmol/ml) × (101.0 ml) = 5.7974 mmol.
  • The no. of millimoles of the base Az (6.0 mmol) is higher than that of the acid HNO₃ (5.7974).
  • This will form a basic buffer in the presence of weak base (Az).

<em>pOH = pKb + log[salt]/[base] </em>

  • [salt] = no. of millimoles of the limiting reactant HNO₃ / total volume = (5.7974) / (181.0) = 0.032 M.
  • [base] = (no. of millimoles of Az – no. of millimoles of HNO₃) / total volume = (6.00 mmol - 5.7974 mmol) / (181.0 ml) = 0.00112 M.
  • pOH = pKb + log[salt]/[base] = 5.96 + log[0.032]/[ 0.00112] = 7.416.
  • pH = 14 – pOH = 14 – 7.416 = 6.58.

<u><em>e) Volume of HNO₃ equal to the equivalence point :</em></u>

  • At the equivalence point the no. of millimoles of the base is equal to that of the acid.
  • Volume of HNO₃ needed for the equivalence point = (6.00 mmol) / (0.0574 mmol/ml) = 104.5 ml  

At the equivalence point:  

  • [Az] = 0.
  • [AzH⁺] = (6.00 mmol) / (80.0 + 104.5 ml) = 0.0325 M.
  • As Ka is very small, the dissociation of AzH⁺ can be negligible.  

Hence, [AzH⁺] at eqm ≈ 0.0325 M.

  • [H+] = √(Ka.C) = √(10⁻⁸˙⁰⁴ x 0.0325) = 1.72 x 10⁻⁵.
  • pH = - log[H+] = - log(1.72 x 10⁻⁵) = 4.76.

<u><em>f) 109 ml of HNO₃: </em></u>

  • No. of milli-moles of H⁺ added from HNO₃ = (0.0574 mmol/ml) × (109 ml) = 6.257 mmol.
  • Which is higher than the no. of millimoles of the base (Az) = 6.0 mmol.
  • After the addition, [H⁺] = (6.257 - 6.00) / (80.0 + 109 mL) = 0.00136 M.
  • As Ka is small and due to the common ion effect in the presence of H⁺, the dissociation of Az is negligible.  
  • pH = -log[H⁺] = -log(0.00136) = 2.87.
3 0
3 years ago
Logarithm of one million
jeyben [28]
Log base 10 of 1000000 is 6
4 0
3 years ago
Read 2 more answers
Other questions:
  • Is cotton yarn a natural resource?
    14·1 answer
  • The oil window is the Choose one:_______
    10·1 answer
  • What are the elements in group 3-12 called
    8·1 answer
  • Molecule of dissimilar elements with a net charge remaining is called
    5·1 answer
  • Help on another one pls ‍♂️!
    15·1 answer
  • When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
    9·1 answer
  • How many parts does CsF ( Cesium Fluoride ) have?
    9·1 answer
  • With initial consent for a warrantless search, police spent three days searching a
    14·1 answer
  • For each of the following choose the variable that will be more favorable in solution formation. A) Weak or Strong Solvent inter
    14·1 answer
  • Describe the location of the negative charges of the atom in j.j thompsons plum pudding model
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!