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3 years ago

What do you call anything that has mass and volume?

Chemistry

2 answers:

serg [7]3 years ago

5 0

A. matter is the correct answer~

lys-0071 [83]3 years ago

3 0

A. Matter. Matter makes up every physical thing in the universe. Everything in the universe takes up space and has mass, therefore, the best answer would be matter.

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An unknown compound was decomposed into 63.2 g carbon, 5.26 g hydrogen, and 41.6 g oxygen. what is its empirical formula?

ira [324]

Step 1:
Divide mass of each element with its M.mass in order to find out moles.

C = 63.2 g / 12 g/mol = Moles = 5.26 moles

H = 5.26 g / 1.008 g/mol =  Moles = 5.21 moles

C = 41.6 g / 16 g/mol =  Moles = 2.6 moles

Step 2:
Select moles of the element with least value and divide all moles of element by it,
C H O
5.26/2.6 : 5.21/2.6 : 2.6/2.6

2.02    : 2.00    :    1

Result:
Empirical Formula =    C₂H₂O

4 0

3 years ago

Iron filings were mixed together with salt crystals. What unique property of iron would be BEST to separate the filings from the

Sedaia [141]

Iron has magnetic properties, so you would just need to hold a magnet over the mixture and the filings will come right out.

4 0

3 years ago

Read 2 more answers

For which compound does 0.26 mole weigh 13g

nalin [4]

0,26mol ------- 13g
1mol ------- x

x = (13g*1mol) / 0,26mol = 50g

It could be Ti or V

6 0

3 years ago

The data were collected over five spring seasons. What is the difference between the number of frogs in the pond when the rainfa

Lunna [17]

Answer: they like deep water

Explanation: they do

3 0

3 years ago

You want to make 500 ml of a 1 N solution of sulfuric acid (H2SO4, MW: 98.1). How many grams of sulfuric acid do you need?

umka21 [38]

Answer:

24.525 g of sulfuric acid.

Explanation:

Hello,

Normality (units of eq/L) is defined as:

$N=\frac{eq_{solute}}{V_{solution}}$

Since the sulfuric acid is the solute, and we already have the volume of the solution (500 mL) but we need it in liters (0.5 L, just divide into 1000), the equivalent grams of solute are given by:

$eq_{solute}=N*V_{solution}=1\frac{eq}{L}*0.5L=0.5 eq$

Now, since the sulfuric acid is diprotic (2 hydrogen atoms in its formula) 1 mole of sulfuric acid has 2 equivalent grams of sulfuric acid, so the mole-mass relationship is developed to find its required mass as follows:

$m_{H_2SO_4}=0.5eqH_2SO_4(\frac{1molH_2SO_4}{2 eqH_2SO_4}) (\frac{98.1 g H_2SO_4}{1 mol H_2SO_4} )\\m_{H_2SO_4}=24.525 g H_2SO_4$

Best regards.

4 0

3 years ago