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elixir [45]
3 years ago
6

For the following reaction, 5.21 grams of nitrogen gas are allowed to react with 5.91 grams of hydrogen gas.

Chemistry
1 answer:
xz_007 [3.2K]3 years ago
7 0

Answer:

Maximum amount of ammonia that can be formed is 6.32 g

Explanation:

The balanced equation is:

N2 + 3H2\rightarrow 2NH3

Moles\ N2 = \frac{5.21g}{28g/mol} =0.186\\\\Moles H2 = \frac{5.21g}{2g/mol} =2.61

N2 is the limiting reactant

Based on the reaction stoichiometry:

1 mole N2 produced 2 moles NH3

therefore, 0.186 mol N2 will yield: 2(0.186) = 0.372 moles NH3

Molar mass NH3 = 17 g/mol

Maximum\ Mass\ NH3 = 0.372 mols*17g/mol=6.32g

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sertanlavr [38]

Answer:

3) NaCl.

Explanation:

<em>∵ ΔTf = iKf.m</em>

where, <em>i</em> is the van 't Hoff factor.

<em>Kf </em>is the molal depression freezing constant.

<em>m</em> is the molality of the solute.

<em>The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. </em>

<em></em>

  • For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<em>So, for sugar: i = 1.</em>

<em>∴ ΔTf for sugar = iKf.m = (1)(Kf)(2.0 m) = 2 Kf.</em>

<em></em>

  • For most ionic compounds dissolved in water, the van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

For NaCl, it is electrolyte compound which dissociates to Na⁺ and Cl⁻.

<em>So, i for NaCl = 2.</em>

<em>∴ ΔTf for NaCl = iKf.m = (2)(Kf)(1.0 m) = 2 Kf.</em>

<em></em>

<em>So, the right choice is: 3) NaCl.</em>

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3 years ago
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What is the molarity of an aqueous solution containing 1.5 moles of calcium chloride in 2.75 L of solution? A. 0.004 M B. 0.55 M
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Answer:

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Explanation:

Step 1: Given data

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M = moles of solute / liters of solution

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