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Flauer [41]
3 years ago
6

Fumaric acid, which occurs in many plants, contains, by mass, 41.4% carbon, 3.47% hydrogen, and 55.1% oxygen. The molecular mass

of this compound is 116 amu. The molecular formula of this compound is
Question 15 options:

CHO


C3H3O


C3H3O3


C4H4O4


C6H6O6
Chemistry
1 answer:
lukranit [14]3 years ago
3 0

Answer:

Explanation:

C = 41.4/12 = 3.43

H = 3.47/1 = 3.47

O = 55.1/16 =3.44

CHO is the skeletal formula (divide each by the lowest number above). The results are close enough to 1 to be 1.

(CHO)_x = 116

C + H + O = 29

(29) _ x = 116

x = 116/29

x = 4

So there area 4 carbons 4 hydrogens and 4 oxygens.

The correct formula is C4H4O4

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SOMEONE HELP ASAP I NEED TO FIND AN ANSWER
astra-53 [7]

Answer:

A) Q + XZ = X + QZ is a single displacement reaction.

B) Q + Z = QZ is a synthesis reaction

C) QT = Q + T is a decomposition reaction

D) QT + XZ = QZ + XT is double replacement reaction.

Explanation:

A) Q + XZ = X + QZ

This is a single displacement reaction because it is one in which one element is substituted for another one in a compound. In this case X is substituted for Q.

B) Q + Z = QZ

This is a synthesis reaction because Q and z combine to form a single product QZ.

C) QT = Q + T

This is a decomposition reaction because the compound QT breaks down to form 2 simpler substances Q and T.

D) QT + XZ = QZ + XT

Thus is a double replacement reaction because QT and XZ have exchanged cations to form new compounds QZ and XT

6 0
2 years ago
1. Starting with 9.3 moles of O 2 , how many moles of H 2 S will be needed and how many moles of SO 2 will
enyata [817]

Answer:

Moles of H₂S needed = 6.2 mol

Moles of SO₂ produced = 6.2 mol

Explanation:

Given data:

Number of moles of O₂ = 9.3 mol

Moles of H₂S needed = ?

Moles of SO₂ produced = ?

Solution:

Chemical equation:

2H₂S + 3O₂      →    2SO₂ + 2H₂O

Now we will compare the moles of oxygen with H₂S.

                  O₂             :           H₂S

                    3             :             2

                   9.3            :         2/3×9.3 = 6.2 mol

Now we will compare the moles of SO₂ with both reactant.

                   O₂             :            SO₂

                    3              :               2

                   9.3            :         2/3×9.3 = 6.2 mol      

                 H₂S             :            SO₂

                    2              :               2

                   6.2            :          6.2 mol      

So 6.2 moles of  SO₂ are produced.

         

6 0
3 years ago
What is the difference between a molecule and a compound?!
KiRa [710]

molecules can be made of two of the same elements whereas a compound is always made of two different elements

3 0
3 years ago
Read 2 more answers
Is water in a kettle boiling a chemical change
Luden [163]
When a kettle is boiling you are able to see the chemical reaction, from the stem leaving the kettle, so yes
Hope this helped  : )

6 0
3 years ago
Read 2 more answers
3) Calculate the percent by mass of 3.55 g NaCl dissolved in 88 g water.
kotykmax [81]

Answer:

The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%

Explanation:

When a solute dissolves in a solvent, the mass of the resulting solution is a sum of the mass of the solute and the solvent.

A percentage is a way of expressing a quantity as a fraction of 100. In this case, the percentage by mass of a solution is the number of grams of solute per 100 grams of solution and can be represented mathematically as:

Percent by mass=\frac{mass of solute}{mass of solution} *100

In this way it allows to precisely establish the concentration of solutions and express them in terms of percentages.

In this case:

  • mass of solute: 3.55 g
  • mass of solution: 3.55 g + 88 g= 91.55 g

Replacing:

Percentbymass=\frac{3.55}{91.55}*100

Percent by mass= 3.88%

<u><em>The percent by mass of 3.55 g NaCl dissolved in 88 g water is 3.88%</em></u>

5 0
3 years ago
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