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notka56 [123]
3 years ago
14

Why the piece of sodium chloride is hard than sodium metal?

Chemistry
1 answer:
Delvig [45]3 years ago
5 0
Sodium chloride is salt, it is an ionic substance thus there is no covalent bonds between the substances only ionic. sodium metal is more malleable but has a higher melting point and doesn't disolve for reasons I think is above your level, the point is sodium is harder
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Gold has density of 19.3 g/cm3; how many grams of gold are in a 16.0 cm3 gold bar?
Andre45 [30]
To determine the mass of gold, we simply multiply the density and volume. Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We do as follows:

mass = density x volume
mass = 19.3 g/cm^3 ( 16.0 cm^3 )
mass = 308.8 g
6 0
3 years ago
Write the reaction rate expressions for the<br> following reactions?<br> 2H2+O2_____2H2O
Nezavi [6.7K]

Answer:

see attachment

Explanation:

3 0
3 years ago
A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. What is the weight/
lara31 [8.8K]

Answer:

A solution is made by dissolving 4.87 g of potassium nitrate in water to a final volume of 86.4 mL solution. The weight/weight % or percent by mass of the solute is :

<u>2.67%</u>

Explanation:

Note : Look at the density of potassium nitrate in water if given in the question.

<u><em>You are calculating </em></u><u><em>weight /Volume</em></u><u><em> not weight/weight % or percent by mass of the solute</em></u>

Here the <u>weight/weight % or percent by mass</u> of the solute is asked : So first convert the<u> VOLUME OF SOLUTION into MASS</u>

Density of potassium nitrate in water KNO3 = 2.11 g/mL

density=\frac{mass}{volume}

Density = 2.11 g/mL

Volume of solution = 86.4 mL

2.11=\frac{mass}{86.4}

mass = 2.11\times 86.4

mass=182.3grams

Mass of Solute = 4.87 g

Mass of Solution = 183.2 g

w/w% of the solute =

= \frac{mass\ of\ solute}{mass\ of\ solution}\times 100

=\frac{4.87}{183.2}\times 100

w/w%=2.67%

8 0
3 years ago
1. A 1500kg car is being lifted by a hydraulic jack attached to a flat plate. Underneath the plate is
AURORKA [14]

Answer:

the pressure in the pipe in the case when there is no net force on the car is  81,726 N/m^2

Explanation:

a. The computation of the pressure in the pipe in the case when there is no net force on the car is shown below

As we know that

Pressure = F ÷ area

Also

F = mg

Now

= (1500 × 9.8) ÷π (0.24)^2

= 81,726 N/m^2

Hence, the pressure in the pipe in the case when there is no net force on the car is  81,726 N/m^2

5 0
3 years ago
The estimate obtained from a sample of which size is likely to be closest to
zubka84 [21]

The answer is C, 85.

8 0
3 years ago
Read 2 more answers
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