Explanation:
The reaction equation will be as follows.

Calculate the amount of
dissolved as follows.

It is given that
= 0.032 M/atm and
=
atm.
Hence,
will be calculated as follows.
=
= 
= 
or, = 
It is given that 
As, ![K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}](https://tex.z-dn.net/?f=K_%7Ba%7D%20%3D%20%5Cfrac%7B%5BH%5E%7B%2B%7D%5D%5E%7B2%7D%7D%7B%5BCO_%7B2%7D%5D%7D)
= 
= 
Since, we know that pH = ![-log [H^{+}]](https://tex.z-dn.net/?f=-log%20%5BH%5E%7B%2B%7D%5D)
So, pH = 
= 5.7
Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.
Answer:
Explanation:
412 ATP's will be generated from the complete metabolic oxidation of tripalmitin (tripalmitoylglycerol)
130 ATP from the oxidation of palmitate
22 ATP from the oxidation of glycerol
Altogether 130 + 22 = 412 ATP will be produced.
Here in case of tripalmitin (tripalmitoylglycerol), we have 51 carbons.
When 51 carbons can produce 412 ATPs
Then 1 carbon will produce how many ATPs = 412 ATPs/ 51 carbon= 8.1 ATPs.
This shows that ATP yield per carbon often oxidized will be 8.1 ATPs
Now we will see the ATP yield in the case of glucose.
Glucose is made up of 6 carbon and complete oxidation of glucose will produce 38 ATPs
When 6 carbons can yield 38 ATPs
Then 1 carbon can yield how many ATPs= 38 ATPs/ 6 carbons= 6.33 ATPs.
So, ATP yield per carbon in case of glucose will be 6.33 ATPs
Upper N upper H subscript 4 upper C l (s) right and left arrows stacked above each other upper N upper H subscript 3 (g) plus upper H upper C l (g)
Explanation:
The given equation is;
NH₄Cl ⇄ NH₃ + HCl
This equation is clearly different from the other ones.
- In the reactant going forward, there is a right and left arrows stacked above each other.
- The symbol is ⇄ and it is used to show reversibility of chemical reactions.
learn more:
Chemical reactions brainly.com/question/3953793
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<span>a. NaNO3: soluble
b. AgBr: insoluble
c. NH4OH: soluble
d. Ag2CO3: insoluble
e. NH4Br: soluble
f. BaSO4: insoluble
g. Pb(OH)2: soluble
h. PbCO3: insoluble</span>
Answer:
For example, a suitcase jam-packed with clothes and souvenirs has a high density, while the same suitcase containing two pairs of underwear has low density. Size-wise, both suitcases look the same, but their density depends on the relationship between their mass and volume. Mass is the amount of matter in an object.