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LUCKY_DIMON [66]
3 years ago
5

about how long does it take for the reaction to reach equilibrium in this concentration versus time graph?

Chemistry
2 answers:
dangina [55]3 years ago
6 0
<h2>Reaction to Reach Equilibrium </h2>

Firstly the substrate concentration increases the rate of reaction also increases but at a certain limit it will stop to increase by adding up the substrate. By raising the enzyme concentration, the maximum reaction rate considerably improves.

The rate of a chemical reaction increases with respect to the substrate concentration increases. Enzymes can exceedingly promote the rate of a reaction. Enzymes convert saturated when the substrate concentration is high.


yarga [219]3 years ago
5 0

Answer: option D. 4.5 seconds.


Explanation:


The equilibrium reaction is H₂O ⇄ H₂ + O₂


The chemical equilibrium is a dynamic one. Two reactions are happening symultaneously: the forward reaction (H₂O → H₂ + O₂) ,to the right, and the reverse reaction (H₂O ← H₂ + O₂), to the left. At equilibrium both reactions have the same rate, which makes that the total, measurable quantity of reactants and products remain constant.


In the figure you see:

  • The vertical axis measures concentration.
  • The horizontal axis measures time (seconds).
  • The two blue lines, the concentrations of H₂ and O₂, become flat (reach a zero slope) between 4 and 5 seconds.
  • The red line, the concentration of H₂O, becomes flat, also, between 4 and 5 seconds.
  • Hence, the concentrations of the reactant and the products do not change after that time meaning that the reaction has reached the equilibrium at about 4.5 seconds.


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Usimov [2.4K]

Answer:

A. volume

Explanation:

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Option A

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2 years ago
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BlackZzzverrR [31]
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3 years ago
HELP!!!! The freezing of methane is an exothermic change. What best describes the temperature conditions that are likely to make
vazorg [7]

<u>Answer:</u> The correct statement is low temperature only, because entropy decreases during freezing.

<u>Explanation:</u>

The relationship between Gibb's free energy, enthalpy, entropy and temperature is given by the equation:

\Delta G=\Delta H-T\Delta S

Where,

\Delta G = change in Gibb's free energy

\Delta H = change in enthalpy

T = temperature

\Delta S = change in entropy

It is given that freezing of methane is taking place, which means that entropy is decreasing and Delta S is becoming negative. It is also given that the reaction is an exothermic reaction, this means that the \Delta H is also negative.

For a reaction to be spontaneous, \Delta G must be negative.

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From above equations, it is visible that \Delta G will be negative only when the temperature will be low.

Hence, the correct statement is low temperature only, because entropy decreases during freezing.

8 0
3 years ago
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0.29

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