Answer:
1.
CH4 + Cl2 → CH3-Cl + HCl
2CH3-Cl +2Na → C2H6
2.
CH3-CH2-OH ---(conc. H2SO4)----> CH2=CH2 + H2O
Explanation:
1. Conversion of methane to ethane
Step 1 - Treat methane with chlorine gas presence of ultraviolet light
CH4 + Cl2 → CH3-Cl + HCl
Step 2 - Treat chloromethane formed in step 1 with the sodium metal and dry ether (Wrutz synthesis)
2CH3-Cl +2Na → C2H6
2. On treating ethanol with excess of concentrated sulfuric acid, it converts into ethene
CH3-CH2-OH ---(conc. H2SO4)----> CH2=CH2 + H2O
Evaporation because the salt would dissolve in the water then boil the water and it will evaporate leaving the salt left in the bowl
Answer:
0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.
Explanation:
The balanced reaction is:
Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Na₂CO₃: 1 mole
- HCl: 2 moles
- NaCl: 2 moles
- CO₂: 1 mole
- H₂O: 1 mole
On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.
In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles= 0.0277 moles
In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl= 0.0554 moles
<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>
Answer:
Here, acceleration due to gravity(a) is assumed as 10m/s².We can also take it as 9.8m/s²
Explanation: