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DedPeter [7]
3 years ago
8

What is the distance between -60 and -10 on

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
3 0

Answer:

50

Step-by-step explanation:

60-10

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vlada-n [284]

x * x = x^2

x * .7 = .7x

-6 * x = -6x

-6 * .7 = -4.2

x^2 + .7x - 6x -4.2

x^2 - 5.3 - 4.2

x = 6

8 0
3 years ago
-10(2x+1/5) in standard form
Svetach [21]

Answer:

-20x-2

Step-by-step explanation:

5 0
2 years ago
A 6 foot wide painting should be center on a 14 foot wide wall. how many feet X should be on each side of the painting
serious [3.7K]

Answer:

4 feet

Step-by-step explanation:

We start by subtracting the 6 from the 14, to get the leftover space on the wall, 8 feet. We then divide that by two, since if the painting is centered there will be two equally-sized spaces on either side of it. This means that X = 4 feet.

6 0
3 years ago
PLEASE HELP WILL GIVE BRAINLIEST
Olin [163]

Answer:

Step-by-step explanation:

in tri ADC and tri BDC

∠ADC =∠BDC = 90

DC is common

AD = BD (given)

triangle ADC ≅ tri BDC by SAS congruency

hence AC = BC by CPCT ( congruent parts of congruent triangles)

hence, BC = 13

8 0
3 years ago
Read 2 more answers
The demand function for a product is p=30−3q where p is the price in dollars when q units are demanded. Find the level of produc
Marina86 [1]

Answer: a) Q= 5units

b) R= $75

Step-by-step explanation:

The maximum revenue is at dR/dq = 0

Revenue = price x quantity of demand = p × q

Substituting p = 30- 3q

R = (30-3q) × q

R= 30q- 3q2 (q2 = q raised to the power of 2)

dR/dq = 30- 6q = 0

6q = 30

q= 30/6= 5

q= 5 units

R = pq= 30q- 3q2

R= 30(5) - 3( 5×5)

R= 150- 75

R= $75

Goodluck...

7 0
3 years ago
Read 2 more answers
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