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4 years ago

Need Help ASAP What is the equation of the line shown in the graph?

Mathematics

1 answer:

marta [7]4 years ago

5 0

The equation of a line is y = mx + b where m is the slope and b is the y-intercept (the point where the line crosses the y-axis). we can look at the graph and see that the line crosses the y axis at y = 4. Therefore, the y-intercept, b, is 4.

Now we must calculate the slope. To do so, we divide the "rise" of the line,
y₂ - y₁ by the "run" of the line x₂ - x₁. We must choose two points (x₁, y₁) and (x₂, y₂) to find the slope. Two points are already given to us, (1, 2) and (4, -4):

m = (-4 - 2)/(4 - 1)

m = -6/3

m = -2

Now that we know the slope and the y-intercept, we can simply plug them back into the equation to find the equation of the line:

y = -2x + 4

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EastWind [94]

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4 years ago

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julsineya [31]

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3 years ago

17 Find the volume of the figure below. (1 Point) V = luh

sveticcg [70]

Answer:

sorry I wish I could help but I'm stupid

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3 years ago

What is the oblique asymptote of the function f(x) = the quantity of x squared plus x minus 2, all over x plus 1?

Archy [21]

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This is a slant asymptote

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3 years ago

the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant

Tamiku [17]

Answer:

The rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters is $24\pi \:\frac{cm^3}{s}$

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

$\frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}$
$\frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}$
The volume of a cone of radius r and height h is given by $V=\frac{1}{3} \pi r^2 h$

We want to find the rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

$\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]$

Substituting the values we know into the above formula:

$\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}$

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3 years ago