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algol [13]
3 years ago
14

Cumulative Cost

Mathematics
1 answer:
Nesterboy [21]3 years ago
8 0
This is too big of a question for only 5 points
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Help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Masja [62]

Answer:

= 6/25 Is the correct answer.

7 0
4 years ago
Read 2 more answers
I need help with finding the answer to a) and b). Thank you!
shtirl [24]

Answer:

\displaystyle \sin\Big(\frac{x}{2}\Big) = \frac{7\sqrt{58} }{ 58 }

\displaystyle \cos\Big(\frac{x}{2}\Big)=-\frac{3 \sqrt{58}}{58}

\displaystyle \tan\Big(\frac{x}{2}\Big)=-\frac{7}{3}

Step-by-step explanation:

We are given that:

\displaystyle \sin(x)=-\frac{21}{29}

Where x is in QIII.

First, recall that sine is the ratio of the opposite side to the hypotenuse. Therefore, the adjacent side is:

a=\sqrt{29^2-21^2}=20

So, with respect to x, the opposite side is 21, the adjacent side is 20, and the hypotenuse is 29.

Since x is in QIII, sine is negative, cosine is negative, and tangent is also negative.

And if x is in QIII, this means that:

180

So:

\displaystyle 90 < \frac{x}{2} < 135

Thus, x/2 will be in QII, where sine is positive, cosine is negative, and tangent is negative.

1)

Recall that:

\displaystyle \sin\Big(\frac{x}{2}\Big)=\pm\sqrt{\frac{1 - \cos(x)}{2}}

Since x/2 is in QII, this will be positive.

Using the above information, cos(x) is -20/29. Therefore:

\displaystyle \sin\Big(\frac{x}{2}\Big)=\sqrt{\frac{1 +  20/29}{2}

Simplify:

\displaystyle \sin\Big(\frac{x}{2}\Big)=\sqrt{\frac{49/29}{2}}=\sqrt{\frac{49}{58}}=\frac{7}{\sqrt{58}}=\frac{7\sqrt{58}}{58}

2)

Likewise:

\displaystyle  \cos \Big( \frac{x}{2} \Big) =\pm \sqrt{ \frac{1+\cos(x)}{2} }

Since x/2 is in QII, this will be negative.

Using the above information, cos(x) is -20/29. Therefore:

\displaystyle  \cos \Big( \frac{x}{2} \Big) =-\sqrt{ \frac{1- 20/29}{2} }

Simplify:

\displaystyle \cos\Big(\frac{x}{2}\Big)=-\sqrt{\frac{9/29}{2}}=-\sqrt{\frac{9}{58}}=-\frac{3}{\sqrt{58}}=-\frac{3\sqrt{58}}{58}

3)

Finally:

\displaystyle \tan\Big(\frac{x}{2}\Big) = \frac{\sin(x/2)}{\cos(x/2)}

Therefore:

\displaystyle \tan\Big(\frac{x}{2}\Big)=\frac{7\sqrt{58}/58}{-3\sqrt{58}/58}=-\frac{7}{3}

5 0
3 years ago
Please tell me the answers!!!
Sophie [7]

Answer:

first one is c second one is c and a

Step-by-step explanation:

8 0
3 years ago
The price of a watch was increased by 10% to £660. What was the price before the increase?
Bad White [126]

Answer:

£600

Step-by-step explanation:

First take if 110% equals to £660 what about 100%

100×660 =66000 ÷ 110 =£600

3 0
3 years ago
What is the quotient of 2x+5/4 ÷ 2x+5/6<br> a. 1/4<br> b. 1/2<br> c. 2/3<br> d. 3/2
Dafna1 [17]
The answer is D: 3/2
6 0
3 years ago
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