Option D would probably be the right choice. Because x is the variable for coins, there would be x amount of quarters, and because there are 150 coins, 150 - x would be the remainder.
Answer: a11 = 3, a12 = 7, a21 = 1, a22 = -4
<u>Explanation:</u>
3x + 7y = 20
x - 4y = 9
A = ![\left[\begin{array}{ccc}3&7&20\\1&-4&9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%267%2620%5C%5C1%26-4%269%5Cend%7Barray%7D%5Cright%5D)
<u>column 1 </u> <u>column 2</u>
row 1: (a11) 3 (a12) 7
row 2: (a21) 1 (a22) -4
Answer:
15
Step-by-step explanation:
The pertinent general formula for this arithmetic progression is
a(n) = a(1) + d(n - 1), where d is the common difference. That difference is d = 4.
Here, a(n) = -5 + 4(n -1)
Therefore, a(6) = -5 + 4(5) = 15
(3x + 2) < -7 or (3x + 2 >7
Explanation/Step by step:
We have| |3x +2| >7
We divide the absolute value inequality into two inequalities
First Inequality (Which is Positive Value)
(3x + 2) >7
Second inequality (Which is the Negative Value)
-(3x + 2) >7
Then you Multiply by- 1 both sides
~And Remember that when you multiply or divide both sides of an inequality by a negative number you must reverse the inequality Symbol.~
So which that be said it would look like this:
(3x +2) < -7
So therefore (3x + 2) < -7 or (3x + 2) >7
Hope this makes since to you!!
I hope this helps as well..
Idk for sure but you have to do 6x6x3.14 and then add 271.4
