Answer:
ω = 0.467 rad/s
Explanation:
given,
tangential force exerted by the person = 37.7 N
radius of merry-go-round = 2.75 m
mass of merry-go-round = 144 Kg
angle = 33.2°
moment of inertia
I = 544.5 kg.m²
torque = force x radius
τ = 37.7 x 2.75
τ = 103.675 N.m
angular acceleration
![\alpha= \dfrac{\tau}{I}](https://tex.z-dn.net/?f=%5Calpha%3D%20%5Cdfrac%7B%5Ctau%7D%7BI%7D)
![\alpha= \dfrac{103.675}{544.5}](https://tex.z-dn.net/?f=%5Calpha%3D%20%5Cdfrac%7B103.675%7D%7B544.5%7D)
α = 0.190 rad/s²
now
,
distance = ![33.2\times \dfrca{2\pi}{360}](https://tex.z-dn.net/?f=33.2%5Ctimes%20%5Cdfrca%7B2%5Cpi%7D%7B360%7D)
d = 0.579 rad
we know,
using equation of rotational motion
t = 2.46 s
angular speed
ω = α x t
ω = 0.19 x 2.46
ω = 0.467 rad/s
Answer:
hey answer in the comment section
<u>Answer</u>
0.00346 hL
<u>Explanation</u>
cL means Centilitre while hL means Hectolitre.
10,000 cL = 1 hL
∴ 34.6 cL = 34.6/10,000 hL
= <em>0.00346 hL</em>
An apple falling to the ground is not an example of centripetal acceleration.
Answer:
T = 0.225 s
Explanation:
The speed of a projectile at the highest point of its motion is the horizontal speed of the projectile. Considering the horizontal motion with negligible air resistance, we can use the following formula:
![v_x = RT\\\\T = \frac{v_x}{R}](https://tex.z-dn.net/?f=v_x%20%3D%20RT%5C%5C%5C%5CT%20%3D%20%5Cfrac%7Bv_x%7D%7BR%7D)
where,
T = Total time of ball in air = ?
R = Horizontal distance covered = 40 m
= horizontal speed = 9 m/s
Therefore,
![T = \frac{9\ m/s}{40\ m}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B9%5C%20m%2Fs%7D%7B40%5C%20m%7D)
<u>T = 0.225 s</u>