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atroni [7]
3 years ago
13

14. The following solution contains errors. Identify the errors and explain why they are incorrect.

Mathematics
1 answer:
IgorC [24]3 years ago
4 0
It’s the restrictions if 2*5 is the answer you would have to simplify.
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21.8

Step-by-step explanation:

1.9 + 9 = 10.9

10.9 x 2 = 21.8

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Given that ​f(x) = x + 4 and ​g(x)​ = x^{2} - x, find ​(f​ + g)(​5), if it exists.
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In the previous lesson, you created SMART goals for yourself to extend from the start of the semester to the end of the semester
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Improve your growth attitude, be more proactive, learn to understand yourself, be persistent despite hurdles, learn to accept your limits, learn how to make successful decisions, practice thankfulness, and stay open-minded to new opportunities are some of the ways that SMART goals can assist you.

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564 which statement is false? It is the sum of 56 tens and 4 ones. The number of hundreds is more than the number of tens. To ge
nirvana33 [79]

Answer:

The number of hundreds is more than the number of tens.

Step-by-step explanation:

The sum of 56 tens and 4 ones= 560 + 4 (true)

The number of hundreds is more than the number of tens.

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7 0
3 years ago
A marketing firm is considering making up to three new hires. Given its specific needs, the management feels that there is a 50%
IRISSAK [1]

Answer:

a) 0.9

b) Mean = 1.58

Standard Deviation = 0.89

Step-by-step explanation:

We are given the following in the question:

A marketing firm is considering making up to three new hires.

Let X be the variable describing the number of hiring in the company.

Thus, x can take values 0,1 ,2 and 3.

P(x\geq 2) = 50\%= 0.5\\P(x = 0) = 10\% = 0.1\\P(x = 3) = 18\% = 0.18

a) P(firm will make at least one hire)

P(x\geq 2) = P(x=2) + P(x=3)\\0.5 = P(x=2) + 0.18\\ P(x=2) = 0.32

Also,

P(x= 0) +P(x= 1) + P(x= 2) + P(x= 3) = 1\\ 0.1 + P(x= 1) + 0.32 + 0.18 = 1\\ P(x= 1) = 1- (0.1+0.32+0.18) = 0.4

\text{P(firm will make at least one hire)}\\= P(x\geq 1)\\=P(x=1) + P(x=2) + P(x=3)\\ = 0.4 + 0.32 + 0.18 = 0.9

b) expected value and the standard deviation of the number of hires.

E(X) = \displaystyle\sum x_iP(x_i)\\=0(0.1) + 1(0.4) + 2(0.32)+3(0.18) = 1.58

E(x^2) = \displaystyle\sum x_i^2P(x_i)\\=0(0.1) + 1(0.4) + 4(0.32) +9(0.18) = 3.3\\V(x) = E(x^2)-[E(x)]^2 = 3.3-(1.58)^2 = 0.80\\\text{Standard Deviation} = \sqrt{V(x)} = \sqrt{0.8036} = 0.89

7 0
3 years ago
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