Ask question

Ask question

All categories

VashaNatasha [74]

3 years ago

9

Determine the gravitational field of Earth at a height 2.88 x 10^8 m above its surface (the height of the moon above Earth). Ear

th's mass is 6.0 x 10^24 kg and its radius is 6.4 x 10^6 m.

1 answer:

ehidna [41]3 years ago

6 0

Answer:

12

Explanation:

You might be interested in

When recyclable materials are sent to a recycling plant, they are often not sorted in any particular way. Plastic materials migh

4vir4ik [10]

Answer:

by applying a magnetic force to recycled materials

8 0

3 years ago

Read 2 more answers

At a particular instant the magnitude of the gravitational force exerted by a planet on one of its moons is 7 × 1021 N. Collapse

9966 [12]

Answer:

Fg = 4.2*10²² N

Explanation:

The gravitational force between any two masses, provided that can be approximated by point masses (comparing their diameters with the distance between them), obeys the Newton's Universal Law of Gravitation, which states that the force (always attractive) is proportional to the product of the masses and inversely proportional to the square of the distance between them (this as a consequence of our Universe being three-dimensional), as follows:

$Fg =\frac{G*m1*m2}{r^{2}}$

So, if one of the masses increases 6 times, the force between them will be directly 6 times larger, so the new magnitude of the force will be as follows:

Fg₂ = Fg₁*6 = 7*10²¹ N* 6 = 4.2*10²² N

7 0

3 years ago

An electric current consists of moving

Slav-nsk [51]

<h3>An electric current consists of moving</h3>

<h2>ANSWER</h2>

A) atoms

<h3><em><u>B) electrons</u></em></h3>

C) elements

D) molecules

3 0

3 years ago

A dog runs 300m North and sees the dog catcher and runs 120 m south .Whats the dogs displacement.The same jogger runs 3 miles ar

ozzi

Answer:

<em>1. 180 m</em>

<em>2. 1.5 miles/hour</em>

<em>3. 0 m/s </em>

Explanation:

The complete question is

A dog runs 300 m North and sees the dog catcher and runs 120 m south Whats the dogs displacement.

A jogger runs north for 3.0 miles. If this took 2.0 hours, what is the jogger’s average velocity in miles per hour?

The same jogger runs 3.0 miles on the track, starting and finishing his run after completing exactly 12 laps around the track. What is his average velocity?

1. Displacement is how far the dog moves from the original starting point.

If the dog runs 300 m north, and then 120 m south, then the displacement from the starting point will be

displacement = 300 - 120 = <em>180 m</em>

2. Displacement of the jogger = 3 miles

Time taken by the jogger = 2 hours

velocity of the jogger = ?

Velocity is = displacement/time

velocity = 3/2 = <em>1.5 miles/hour</em>

3. velocity = displacement/time

if the jogger completes exactly 12 laps around the track, then the jogger will return to the starting point. This means that the jogger's displacement from the starting point is 0 miles

Jogger's velocity will therefore be = <em>0 m/s </em>

8 0

3 years ago

A train is travelling at 50 m s−1 when the driver applies the brakes and gives the train a constant deceleration of magnitude 0.

ryzh [129]

Answer:

The strain will come to rest after traveling some distance.

distance traveled = 2500 m

Explanation:

The strain will come to rest after traveling some distance.

Applying,

s = ut+at²/2................... Equation 1

Given: u = initial velocity, a = deceleration, t = time, s = distance

From the question,

Given: u = 50 m/s, t = 100s, a = -0.5 m/s²(deceleration)

Substitute these values into equation 1

s = 50(100)+(-0.5)(100²)/2

s = 5000-2500

s = 2500 m

Hence the distance traveled is 2500 m

3 0

3 years ago