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arlik [135]
3 years ago
5

What is Newtons third law

Physics
2 answers:
Feliz [49]3 years ago
6 0
<span> For every action, there is an equal and opposite reaction. </span>
Vilka [71]3 years ago
3 0
 Newton's third law<span> is for every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. </span>
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Go around your house and hit (or tap) ten different objects. The objects should be different shapes and made of different materi
Blababa [14]

Answer:

 

Explanation:

go around your house and tap random objects. For example, a sink. What noise did it make? was it loud or quiet? was it soft or hard? I hope this helps

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3 years ago
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an object of mass m is rotating about a fixed axis with angular momentum l. its moment of inertia about this axis is i. what is
Tems11 [23]

The Kinetic energy would be 1/2IL².

<h3>What is Rotational Kinetic energy ?</h3>

  • Rotational energy also known as angular kinetic energy is defined as: The kinetic energy due to the rotation of an object and is part of its total kinetic energy. Rotational kinetic energy is directly proportional to the rotational inertia and the square of the magnitude of the angular velocity.

As we know linear Kinetic energy = 1/2mv²

 where m= mass and v= velocity.

Similarly rotational kinetic energy is given by = 1/2IL²

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To know more about the Kinetic energy , visit:

brainly.com/question/29807121

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8 0
1 year ago
g (12 points) The time between incoming phone calls at a call center is a random variable with exponential density p(x) = 1 r e
rusak2 [61]

Answer:

(1)p(x)\geq 0\\(2)\int_{0}^{\infty} p(x) dx=0

Explanation:

A function f(x) is a Probability Density Function if it satisfies the following conditions:

(1)f(x)\geq 0\\(2)\int_{0}^{\infty} f(x) dx=0

Given the function:

p(x)=\dfrac{1}{r}e^{-x/r} \: on\: [0,\infty), where\:r=\dfrac{20}{ln(2)}

(1)p(x) is greater than zero since the range of exponents of the Euler's number will lie in [0,\infty).

(2)

\int_{0}^{\infty} p(x)=\int_{0}^{\infty} \dfrac{1}{r}e^{-x/r}\\=\dfrac{1}{r} \int_{0}^{\infty} e^{-x/r}\\=-\dfrac{r}{r}\left[e^{-x/r}\right]_{0}^{\infty}\\=-\left[e^{-\infty/r}-e^{-0/r}\right]\\=-e^{-\infty}+e^{-0}\\SInce \: e^{-\infty} \rightarrow 0\\e^{-0}=1\\\int_{0}^{\infty} p(x)=1

The function p(x) satisfies the conditions for a probability density function.

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3 years ago
What does the pupil of the eye controls
Alja [10]
The correct answer would be D
5 0
4 years ago
List at least 3 ways for you to represent your data graphically
yawa3891 [41]
1. circle graph
2. Bar graph
3. line graph

hope this helps
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