Answer:
) pulls the ladder in the direction opposite
Explanation:
This is in line with lenz law that states that the magnetic field induced in a conductor act to oppose the magnetic field that produced it
The transmission of light waves is usually done through cornea of the eyes, then move through another opening which is regarded as pupil before it will get to the retina.
- Light waves can be regarded as moving energy which contains microscopic particles known as photons.
- The vision of the eye can be completed through the light wave passing through the components of the eyes and this process goes thus;
- Light will move through the (cornea) which is situated at the front area of the eyes into lens.
- Then both the cornea and the lens give room for the focusing of the light rays to the retina which is situated at the back of the eye .
- Then through the help of the cells in the retina, the light will be absorbed and then be converted to electrochemical impulses and then transfer it to the brain as well as optic nerve.
Therefore, light wave are form of tiny microscopic particles.
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Answer:
4.465 m
Explanation:
Taken the beam to be uniform, then the center of gravity will act at the mid-point of the beam. The mid point = 11 / 2 = 5.5 m
since the boy can walk to the end of the beam without falling,
then the torque ( moment of the force) by beam = torque by students at the end of the beam
let the distance of the boy = x
220 ( 5.5 - x ) = 51 × x
1210 - 220 x = 51 x
1210 = 51 x + 220 x
1210 = 271 x
x = 1210 / 271 = 4.465 m
Answer: 1350J
Explanation:
To solve this, we are going to use the formula for calculating potential difference which is:
Potential difference (V) = Work done (W) / Total charge (C)
Therefore,
9 volts = Work done / 150
Work done = 150 × 9 = 1350J
Answer:
The new energy is 1/16 of the original energy
Explanation:
A capacitor is an electric device which is able to store charge when it is connected to a power supply.
The energy stored in a capacitor is given by the equation
where:
Q is the charge stored on the capacitor
C is the capacitance of the capacitor
For the capacitor in this problem, initially we have
E = 7 J (energy) when the charge stored is Q and the capacitance is C
Later, the charge is decreased to 1/4 of its original value, so the new charge is
Since the capacitance remains the same, the new energy is
Therefore, the new energy is 1/16 of the original energy.
