Answer:
100,200J of heat is required to convert 0.3kg of ice of 0°C to water at same temperature.
Explanation:
Heat = mass * lf
Latent heat of fusion (lf) of water is 334J/g
Heat = 300g * 334 J/g
Heat = 100,200J of heat
Rock is completely immersed in hot water. By the second law of thermodynamics, thermal energy or heat is transferred from substance with higher temperature to substance with lower temperature until they come to thermal equilibrium i.e. both at same temperature.
It is given here that rock is at 20°C which is at lower temperature than water at 80°C. ∴Heat or thermal energy flows from water to rock. So, right choice is-
A. The water gives the rock thermal energy and gets no thermal energy in return.
Answer:
The mass flow rate is 2.37*10^-4kg/s
The exit velocity is 34.3m/s
The total flow of energy is 0.583 KJ/KgThe rate at which energy leave the cooker is 0.638KW
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Answer:
If I’m correct 300 joules
Explanation:
