The percentage increase is 46%.
Original number/start = $15
End number = $22
Increase = $22 - $15 = $7
% increase = Increase ÷ Original Number × 100
Substitute in known values
% increase = 7 ÷ 15 × 100
Divide
% increase = 0.46 × 100
Multiply
% increase = 46%
The percentage increase is 46%.
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Answer:
1st Option is correct
Step-by-step explanation:
Just keep adding 150 to see the results
Answer: A. y = 16 x
B. 8 days
Step-by-step explanation:
A) Here, 16 Fluid ounces of milk is used for breakfast every morning.
In one day the consumption of milk = 16 fluid ounces
In x days the consumption of milk = 16 x fluid ounces
Thus, if y be the total milk in ounces that is used in x days,
The required function,
y = 16 x
B) In 1 day, consumption of milk = 16 ounces
⇒ 
⇒ 
⇒ 
Since, 128 ounces = 1 gallon
⇒ 
In 8 days, 1 gallon of milk will consumed.