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3 years ago

The sum of three consecutive odd numbers is 105. What is the largest of these numbers

Mathematics

1 answer:

puteri [66]3 years ago

3 0

Answer:

33,35,37

The largest of these numbers is 37.

Step-by-step explanation:

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MariettaO [177]

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3 years ago

What postulate or theorem can be used to prove that ΔEFG ≅ ΔJHG?

OlgaM077 [116]

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3 years ago

-. In Ms. Nice's class of 9 students, the average

frutty [35]

Answer: 94.5

Step-by-step explanation:

If average of 9 students is 94, their total will be 94x 9 = 846

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945/10 = 94.5

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3 years ago

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3 years ago

Expand and combine like terms (3z^5 +7z^2)^2

AVprozaik [17]

Answer:

$\displaystyle{(3z^5+7z^2)^2 = 9z^{10}+42z^7 + 49z^4 }$

Step-by-step explanation:

Since it's a perfect square, we can simply use the formula:

$\displaystyle{(ax+by)^2 = a^2x^2+2abxy+b^2y^2}$

Given the perfect square expression $\displaystyle{(3z^5+7z^2)^2}$ . Apply perfect square formula:

$\displaystyle{(3z^5+7z^2)^2 = 3^2(z^5)^2+2(3)(7)(z^5)(z^2) + 7^2(z^2)^2 }$

Knowing laws of exponent is mandatory when it comes to algebra. Recall that:

$\displaystyle{(a^m)^n = a^{mn}}\\\\\displaystyle{a^m \cdot a^n = a^{m+n}}$

Apply laws of exponent to simplify the terms or expression:

$\displaystyle{(3z^5+7z^2)^2 = 9z^{10}+42z^7 + 49z^4 }$

Since there are no like-terms to do operation with (these terms have different degrees so they are not considered to be like-terms.) Therefore, the final answer is:

$\displaystyle{(3z^5+7z^2)^2 = 9z^{10}+42z^7 + 49z^4 }$

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1 year ago