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shtirl [24]
3 years ago
5

Simplify x^0 y^-3/x^2y^-1

Mathematics
2 answers:
galben [10]3 years ago
8 0

The answer is 1/x^2y^2

Zolol [24]3 years ago
6 0

The given expression is \frac{ {x}^{0} y  { - }^{3} }{ {x}^{2}y { - }^{1} }

We know that any number raised with zero power equals 1. Thus, {x}^{0}  = 1

Hence, the expression becomes

\frac{y { - }^{3} }{ {x}^{2} y { - }^{1} }

Now, apply the quotient rule,\frac{ {x}^{ \alpha } }{ {x}^{b} }  =  {x}^{ \alpha  - b}

Using this rule, we have

\frac{1}{ {x}^{2} y { - }^{1 - ( - 3)} }

=  \frac{1}{ {x}^{2} y { - }^{1 + 3} }

<h3>= \frac{1}{ {x}^{2} {y}^{2}  }</h3>

Hence, the simplified expression is \frac{1}{ {x}^{2} {y}^{2}  }

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4 years ago
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A concentric-tube heat exchanger cools hot water owing at 1 kg/s from 80C to 30C. It uses air owing at 5 kg/s to perform this co
nordsb [41]

Answer:

The log-mean-temperature-difference is 24.03⁰C

Step-by-step explanation:

First we need to know if the heat exchanger is in parallel flow or counter-flow. However, counter flow arrangement is best used to recover heat.

L.M.T.D for counter flow is given as;

L.M.T.D =\frac{(T_h_f_1 -T_c_f_2)-(T_h_f_2 -T_c_f_1)}{2.3log[\frac{T_h_f_1 -T_c_f_2}{T_h_f_2 -T_c_f_1}]}

where;

Thf₁ is the initial temperature of the hot fluid = 80°C

Tcf₂ is the final temperature of the cold fluid = 51.5°C

Thf₁ - Tcf₂ = 80 - 51.5 = 28.5⁰C

Thf₂ is the final temperature of the hot fluid = 30°C

Tcf₁ is the initial temperature of the cold fluid = 10°C

Thf₂ - Tcf₁ = 30 - 10 = 20⁰C

L.M.T.D = \frac{28.5 -20}{2.3Log[\frac{28.5}{20}]} \\\\L.M.T.D = \frac{8.5}{0.3538} =24.03^oC

Therefore, the log-mean-temperature-difference is 24.03⁰C

3 0
3 years ago
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(Please Help) Drag a statement or reason to each box to complete this proof.
SOVA2 [1]

Answer:

see the explanation and the attached figure

Step-by-step explanation:

we have

-2(x+1)=8 ----> given

Divide by -2 both sides

-2\frac{(x+1)}{-2} =\frac{8}{-2} ----> by Division Property of Equality

Simplifying

x+1=-4

Subtract 1 both sides

x+1-1=-4-1 ----> by Subtraction Property of Equality

Simplifying

x=-5

6 0
4 years ago
If f(x) = 11x – 5, then f^-1(x)=
MAVERICK [17]

Answer: f^-^1(x)=\frac{x+5}{11}

Step-by-step explanation:

To find the inverse, you replace the x with y, and y with x.

x=11y-5                       [add 5 on both sides]

x+5=11y                       [divide both sides by 11]

\frac{x+5}{11} =y

f^-^1(x)=\frac{x+5}{11}

8 0
3 years ago
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