3 years ago

Find the following probabilities based on the standard normal variable Z. (You may find it useful to reference the z table

Mathematics

1 answer:

hammer [34]3 years ago

7 0

Answer:

Step-by-step explanation:

a. P(Z > 1.12) = 1-N(1.12) = 1-0.8686431=0.1313569

b. <em>P(Z S-2.35)</em> => P(Z <= 2.35) = 0.009386706

(please check interpretation of question b)

c. <em>POSZ s 1.34)</em> => P(0 <= Z <= 1.34) = 0.9098773 - 0.5 = 0.4098773

(please check interpretation of question c)

d. P(-0.8 sz s 2.44) => P(-0.8 <= 2.44) = 0.9926564 - 0.2118554 = 0.780801

(please check interpretation of question d)

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