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nevsk [136]
3 years ago
11

You are given a sample block of an unknown metal. the block displaces 3.24 ml of water and has a mass of 62.5429 g. what is the

density of 7 the unknown metal? what is the metal
Chemistry
2 answers:
Mariulka [41]3 years ago
7 0

Density = mass / volume so density = 62.5429 / 3.24 = 19.3 g/ml. This is the density of gold.


diamong [38]3 years ago
5 0

Explanation:

The given data is as follows.

          Volume = 3.24 ml,      mass = 62.5429 g

As we know that density is the mass of object divided by the volume occupied by it.

Mathematically,     Density = \frac{mass}{volume}

Therefore, calculate the density of given unknown metal as follows.

               Density = \frac{mass}{volume}

                             = \frac{62.5429 g}{3.24 ml}

                             = 19.30 g/ml

Hence, density of the given unknown metal is 19.30 g/ml.

Gold is the element which has a density of 19.30 g/ml.

Thus, we can conclude that given unknown metal has a density of 19.30 g/ml and name of this metal is gold.

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In which of the following are the symbols and names for the ions given correctly?
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What volume (in liters, at 703 k and 2.04 atm) of chlorine gas is required to react with 3.39 g of p?
Natali5045456 [20]

The volume of chlorine required is 7.71 L.

The reaction between phosphorus and chlorine is:

2P + 5Cl₂→ 5PCl₅

Therefore, 2  moles of P requires 5 moles of chlorine to react with it.

Given mass of P =3.39 g

Molar mass of P=30.97 g/mol

No. of moles of P = given mass/ molar mass = 3.39 / 30.97 = 0.109 moles

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V = 0.2725 x 0.0821 x 703 / 2.04

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brainly.com/question/3637553

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