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3 years ago

What is Constituent Element?

Chemistry

2 answers:

charle [14.2K]3 years ago

6 0

Answer:

hope it helps...

Explanation:

a constituent element, material, etc.; component. a person who authorizes another to act in his or her behalf, as a voter in a district represented by an elected official. Grammar. an element considered as part of a construction. Compare immediate constituent, ultimate constituent.

If this helped please comment...

Vika [28.1K]3 years ago

4 0

A constituent element, material, etc.; component. a person who authorizes another to act in his or her behalf, as a voter in a district represented by an elected official. Grammar. an element considered as part of a construction. Compare immediate constituent, ultimate constituent.

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What is the pH of a solution that<br> contains [H+]=3.18 x 10^-8 M?

Xelga [282]

Answer:

7.50

Explanation:

pH=-log(H3O+)

- Hope that helps! Please let me know if you need further explanation.

4 0

3 years ago

A solution is 40 cetic acid by mass. the density of this solution is 1.049 g/ml. Calculate the mass of pure acetic acid in 220 m

taurus [48]

The mass of pure acetic acid in 220 ml of the given solution at 20°C is 92.311 g

<h3>What is Acetic acid?</h3>

Acetic acid is a type of carboxylic acid and also known as ethanoic acid

Its formula is CH₃COOH.

It is an organic compound and is a colorless liquid

It is mostly used in the production of vinegar

40 % acetic acid by mass means,

40 g of acetic acid is dissolved in 100 g of solution.

The density of solution at 20°C,

$\rho = 1.049 g/ml$

We know,

$\rho = \frac{m}{V}$

$V = \frac{m}{\rho}$

The volume of the solution, $V = \frac{100}{1.049}$ = 95.33 ml

95.33 ml of solution contains 40 g of pure Acetic acid

220 ml of solution contains $\frac{40 \times 220}{95.33}$ = 92.311 g of pure Acetic acid

Thus, the mass of pure Acetic acid in 220 ml of solution at 20°C is 92.311 g

Learn more about acetic acid:

brainly.com/question/24304533

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7 0

2 years ago

A sample of gas with an initial volume of 28.4 Liters at a pressure of 725 mmHg and a temperature of 305 K is compressed to a vo

Lerok [7]

Answer:

The final pressure is 2.25 atm or 1710 mm Hg

Explanation:

Step 1: Data given

The initial volume = 28.4 L

The initial pressure = 725 mm Hg ( = 725/760 atm) = 0.953947 atm

The initial temperature = 305 K

The new volume is 14.8 L

The new temperature = 375 K

Step 2: Calculate the new pressure

(P1*V1)/T1 = (P2*V2)/T2

⇒ with P1 = the initial pressure = 725 mmHg = 0.953947 atm

⇒ with V1 = the initial volume = 28.4 L

⇒ with T1 = The initial temperature = 305 K

⇒ with P2 = the new pressure = TO BE DETERMINED

⇒ with V2 = the new volume = 14.8 L

⇒ with T2 = the new temperature = 375 K

(0.953947 * 28.4)/305 = (P2 * 14.8)/375

P2 = 2.25 atm = 1710 mm Hg

The final pressure is 2.25 atm or 1710 mm Hg

6 0

3 years ago

How many liters of o2 do you have if you have 5.8 moles of o2

polet [3.4K]

Answer:

130 Liters

Explanation:

if 1 mol is 22.4 L, then 5.8 mol is 130 L (129.92 but use sig figs)

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3 years ago

What is the name of the chart that organizes elements in order of chemical properties?

solong [7]

It is called the periodic table

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3 years ago