If xy=0 assume that x and y=0
so
(2x-8)(7x+5)=0
assume
2x-8=0 and 7x+5=0
solve each
2x-8=0
2x=8
x=4
7x+5=0
7x=-5
x=-5/7
so x=-5/7 or 4
Answer:
<u>Answer (a):</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
<u>Answer (b)</u>
9 large dogs.
Step-by-step explanation:
Paws at Play made a total of $1234 grooming 22 dogs.
Paws at Play charges $43 to groom each small dog and;
$75 for each large dog.
Let the number of small dogs be 's'
And the number of large dogs be 'l'
<u>A system of equations will be:</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;
43s + 43l = 946 ... (i)
43s + 75l = 1234 ... (ii)
Subtracting (i) from (ii) we get;
32l = 288 , l =
= 9
So there are 9 large dogs.
Find values that add to 5 and multiply to 6
so the answer would be (x+5)(x+1)
Answer:
B) y=10
Step-by-step explanation:
10+10=20
20*2/5=8