Question

On a coordinate plane, a line goes through (negative 3, negative 3) and (negative 1, 5). What is the equation of the line parallel to the given line with an x-intercept of 4? y = x +

Answer 1

Answer:

Step-by-step explanation:

A line that is parallel to the line that goes through (-3, -3) and (-1, 5) will have the same slope as the one we will find when we plug those numbers into the slope formula. Let's do that first:

$m=\frac{5-(-3)}{-1-(-3)}=\frac{5+3}{-1+3}=\frac{8}{2}=4$ so the line we need to write has a slope of 4. Moving on...

If the x-intercept we need is 4, that means that we need to understand what an x-intercept is. The x-intercept exists where y = 0; so what we need to do is to write the equation of the line that has a slope of 4 and passes through the point (4, 0). Doing that:

y - 0 = 4(x - 4) and

y = 4x - 16