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vladimir2022 [97]
3 years ago
15

Can you please explain how you did it

Mathematics
1 answer:
Nadya [2.5K]3 years ago
3 0

Answer:

205

Step-by-step explanation:

10 1/4 *20=(10*4+1)/4 *20=41*20/4=41*5=205

the rule is...... a b/c=(a*c+b)/c

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Which expression is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the thi
zaharov [31]

The expression is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power is; Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power

<h3>How to solve exponents?</h3>

We want to find the expression that is equivalent to 1.5 raised to the fifth power divided by 0.7 raised to the fourth power, all raised to the third power.

The sentence above can be expressed as;

((1.5⁵)/(0.7⁴))³

This can be broken down into;

[1.5^(5 * 3)]/(0.7^(4 * 3))

1.5¹⁵/0.7¹²

Looking at the options, the only correct one is;

Option A; 1.5 raised to the fifteenth power divided by 0.7 raised to the twelfth power

Read more about Exponents at; brainly.com/question/11975096

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3 0
1 year ago
1. A box of fruit has 12 plums and 15 bananas. The
sukhopar [10]

Answer:

12p x (15 x 25) I might not be correct :')

3 0
3 years ago
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How do you find the slope of y=-4/3x - 1?
Brut [27]
I can't think of what the form is called, but the slope is in that equation.

y=mx+b

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8 0
3 years ago
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In in 10 to the sixth power of the 10 is the what
Svetach [21]

10 to the sixth power is 1,000,000. Any number to the tenth power is the number 1 in front of the  number of zeros that is equal to the exponent.

4 0
3 years ago
Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

which means the series converges everywhere (independently of x), and so the radius of convergence is infinite.
3 0
3 years ago
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