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Kitty [74]
3 years ago
7

2x^5-3x^4-5x^3-15x^2-207x+108zeros: 3ifind the remaing zeros

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
4 0
The real solutions are {x=-3, x= \frac{1}{2} , x=4}.

The imaginary solutions are {x=-3i, x=3i}.
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