<h3>Given</h3>
4 hundreds flats; 5 tens rods; 2 ones cubes
<h3>Find</h3>
The number of hundreds flats in each of 2 equal piles
<h3>Solution</h3>
When 4 flats are divided into two equal groups, each group will have ...
... 2 flats
_____
You can imagine doing this the way a card dealer might: first put 1 flat in each of 2 piles, then do the same for the remaining 2 flats. Each pile will end up with 2 flats.
— — — — —
You will have a problem if you continue with the tens rods. There is an odd number of those, so one of them will have to be exchanged for 10 ones cubes.
Answer:
(82/3, -111/2) or x=82/3, y=-111/2
Step-by-step explanation:
Answer:
Step-by-step explanation:
HEY
hello lol srry I don't know what to do
Answer:
45 i think i dont know
Step-by-step explanation:
m
∠
2
=
x
holds true.
Complementary angles have a sum of
90
˚
. Thus, if
∠
1
and
∠
2
are complementary,
m
∠
1
+
m
∠
2
=
90
Substitute the equivalent forms of these angle measurements
(
x
,
x
)
.
x
+
x
=
90
Solve algebraically.
2
x
=
90
x
=
45
Each angle is
45
˚
.
