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3 years ago

11

There are 2 pounds of jellybeans in the jar if you divided jellybeans jellybeans evenly into bags employees to 1 pound into each

bag how many bags will you use

1 answer:

Semenov [28]3 years ago

3 0

Answer:

The number of bags used is 2 bags

Step-by-step explanation:

The mass of the jellybeans in the jar = 2 lbs

The mass divided evenly into bags = 1 pound each

Therefore the operation applied to the jar of jellybean is a division by 1 lb/bag, therefore, we have;

The number of bags used = 2 lbs/(1 lb/bag) = 2 bags

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The local dairy farm has 3.7×10^3 cows and each cow produces 2.6×10^3 gallons of milk each year. How many gallons are produced a

Nadusha1986 [10]

Answer:

96.2*10^5 gallons

Step-by-step explanation:

gallons of milk produced by 1 cow = 2.6×10^3

No. of cows with local dairy farm = 3.7×10^3

Total of gallons of milk produced by farm = gallons of milk produced by 1 cow * No. of cows with local dairy farm = 2.6×10^3 * 3.7×10^3 = 9.62*10^6

we have to write it in standard form = 96.2*10^5 gallons

i can be also written as = 9,620,000 Gallons.

9.62 Million Gallons of milk is produced by local dairy farm Yearly.

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3 years ago

The distance between two cities on a map measures 3.75 inches.The scale on the map shows 2 inches is equal to 50 miles.How many

Ede4ka [16]

Answer:93.75 miles

Step-by-step explanation:

Given

Distance between two cities is $3.75\ inches$

and Map 2 shows 2 inches is equal to $50\ miles$

So each inch is equal to $25\ miles$

So $3.75\ in.$ measures

$\Rightarrow =3.75\times 25=93.75\ miles$

So cities are $93.75\ miles$ apart

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3 years ago

Which of the following statements are true?

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3 years ago

Examination of court records in a particular state shows that the mean sentence length for first-offense drug dealers is 26 mont

Zigmanuir [339]

Answer and explanation:

Given : Examination of court records in a particular state shows that the mean sentence length for first-offense drug dealers is 26 months with a standard deviation of 2 months. The records show that the sentence lengths are normally distributed.

i.e. Mean $\mu=26$ , Standard deviation $\sigma=2$

Using Z-score formula,

$Z=\frac{\bar{x}-\mu}{\sigma}$

1) What is the Z score for a 23 month sentence length? What is the probability of getting a sentence below that?

The Z score value for a $\bar{x}=23$ is given by,

$Z=\frac{23-26}{2}$

$Z=\frac{-3}{2}$

$Z=-1.5$

The probability of getting a sentence below that is $P(X$

i.e. $P(X$

$P(X$

2) A defense attorney is concerned that his client's sentence was unusually harsh at 30 months. What percent of sentences are 30 months or longer? Calculate the Z score and report the area.

The Z score value for a $\bar{x}=30$ is given by,

$Z=\frac{30-26}{2}$

$Z=\frac{4}{2}$

$Z=2$

The probability of getting a sentence below that is $P(X\geq 30)$

i.e. $P(X\geq 30)=1-P(Z\leq 2)$

$P(X\geq 30)=1-0.977$

$P(X\geq 30)=0.023$

Into percentage, $P(X\geq 30)=2.3\%$

3) Would you consider a 30 month sentence harsh? Explain

Since the percentage for 30 months or greater is harsh because the smaller value of percentage of $P(X\geq 30)=2.3\%$

7 0

3 years ago