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Artemon [7]
3 years ago
8

Write an equation in point slope form of the line passes through the point (3,5) and has a slope of m=-1

Mathematics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

The answer is y= -1x+8

Step-by-step explanation:

y=mx+b

m= -1

y-y=m(x-x1)

y-5=-1(x-3)

y-5=-1x+3

+5 +5

y=-1x+8

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X + 8(y + 4) − (5y − x)
Anna11 [10]

Answer:

2x+3y+32

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Prove that :( 1 + 1/<img src="https://tex.z-dn.net/?f=tan%5E%7B2%7DA" id="TexFormula1" title="tan^{2}A" alt="tan^{2}A" align="ab
Aliun [14]

Answer:

See explanation

Step-by-step explanation:

Simplify left and right parts separately.

<u>Left part:</u>

\left(1+\dfrac{1}{\tan^2A}\right)\left(1+\dfrac{1}{\cot ^2A}\right)\\ \\=\left(1+\dfrac{1}{\frac{\sin^2A}{\cos^2A}}\right)\left(1+\dfrac{1}{\frac{\cos^2A}{\sin^2A}}\right)\\ \\=\left(1+\dfrac{\cos^2A}{\sin^2A}\right)\left(1+\dfrac{\sin^2A}{\cos^2A}\right)\\ \\=\dfrac{\sin^2A+\cos^2A}{\sin^2A}\cdot \dfrac{\cos^2A+\sin^A}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A}\cdot \dfrac{1}{\cos^2A}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

<u>Right part:</u>

\dfrac{1}{\sin^2A-\sin^4A}\\ \\=\dfrac{1}{\sin^2A(1-\sin^2A)}\\ \\=\dfrac{1}{\sin^2A\cos^2A}

Since simplified left and right parts are the same, then the equality is true.

3 0
3 years ago
A bag contains 4 red marbles, 3 white marbles, and 7 blue marbles. You pick a marble without looking. Find the probability of dr
astra-53 [7]
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6 0
3 years ago
Evaluate the expression for the given values.
blagie [28]

we have given an expression mx-y.

we have given the value of x,y and m .

m=5,x=3,y=8.

we need to find the value of expression mx-y.

we need to plug the respective values and solve.

mx-y=(5)*(3)-(8)=15-8=7..

7 is the value of expression mx-y.

3 0
4 years ago
I need help what is (6x9)+(7+3)=
Inessa05 [86]

Answer:

64

Step-by-step explanation:

Evaluate the parenthesis before doing the addition, that is

(6 × 9) + (7 + 3)

= 54 + 10

= 64

3 0
3 years ago
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