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aleksandrvk [35]

3 years ago

11

Kim had 20 minutes to do a three-problem quiz. She spent 9 3/4 minutes on question A and 5 1/2 minutes on question B. How much t

ime did she have left for question C?

2 answers:

SVEN [57.7K]3 years ago

6 0

4 minutes and 45 seconds

dezoksy [38]3 years ago

4 0

4:45 because 9:45+5:30=15:15. When subtracted from so that equals 4:45

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nikitadnepr [17]

Eight is the answer.

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Scores on a certain IQ test are knownto have a mean of 100. A random sample of 43 students attend a series of coaching classes b

NeX [460]

Answer:

Part 1

Type II error

Part 2

No ; is not ; true

Step-by-step explanation:

Data provided in the question

Mean = 100

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3 years ago

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Kaylin is tracking the progress of a plant’s growth. Today the plant is 4 cm high. The plant grows 0.5 cm per day.

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Step-by-step explanation:

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3 years ago

For each pair figures, find the ratio of the area of the first figure to the area of the second. 14mm 7mm

Paraphin [41]

The ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

<h3>Ratio of the areas of similar figures </h3>

From the question, we are to determine the ratio of the area of the<u> first figure</u> to the area of the <u>second figure</u>

<u />

The two figures are similar

From one of the theorems for similar polygons, we have that

If the scale factor of the sides of <u>two similar polygons</u> is m/n then the ratio of the areas is (m/n)²

Let the base length of the first figure be ,m = 14 mm

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∴ The ratio of their areas will be

$(\frac{14 \ mm}{7 \ mm})^{2}$

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$=\frac{4}{1}$

= 4:1

Hence, the ratio of the area of the <u>first figure</u> to the area of the <u>second figure</u> is 4:1

Learn more on Ratio of the areas of similar figures here: brainly.com/question/11920446

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2 years ago