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3 years ago

Two sources of error and precaution in the centre of gravity experiment

Physics

1 answer:

Karo-lina-s [1.5K]3 years ago

7 0

Answer:

The answer to this question is given below in this explanation sections.

Explanation:

The weight of an object is concentrated at the center of gravity.The term center of gravity is used interchangeably with center of mass.For a symmetrical object the center of mass is located at the geometric center of the object.If the object is not symmetric we can determined the center of mass using the mentioned below.

Materials:

cardboard
weight(washer,bolt,or fishing weight)
hole punch

pencil

Procedure:

Cut the cardboard into a strange shape.Do not use a circle,square,rectangle,or any other common geometric shape.
Punch a hole near the edge of the cut-out cardboard piece and hang it from a nail.
Place the weight, a washer or bolt, on a thread and tie it off.
Hang the thread and weight from the nail in front of the cardboard.
use a pencil to draw a plumb line down the cardboard where the thread touches.This mark your center line from that hanging point.

conclusion:

What would happen to the center of gravity of the shape if you were to spin it freely?

center of gravity experiment:

Balance a ruler with a hammer.Take a rubber band or string and make a loose loop around the hammer and ruler. Make sure the end of the hammer is touching the ruler,and then positions the ruler at the edge of the table.
Balance two forces with a toothpick.A common magic trick using the properties of center of gravity.The two forks are balanced on the edge of the glass by a toothpick.
Stand with your back and feet against a wall.Have someone place quarter on the floor at your feet.Try to pick it cup.Most people cant make these adjustments.
Stand against a wall sideways with your arm and leg touching the wall,with nothing to from the out away hold onto.Try to lift your other leg straight out away from the wall.you wont be able to do it.
The girls away win chairs lifting challanges place dining chairs against a wall.Bend over the chair so that your head touches the wall and you upper body is parallel to the floor.lift the chair to your chest to your chest and then try to stand up.

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Question 23

bonufazy [111]

If the gymnast mass were doubled, her height (h) from the top of the board would be as follows,

с Stay the same

Explanation:

The Mass of an object or body does not affect the acceleration due to gravity in any kind of way.
Light weight objects accelerate more slowly than the heavy objects because when the forces other than the gravity also plays a major role.
Mass increases of a body when an object has higher velocity or the speed.
The greater the force of gravity, it would give a direct impact on the object's acceleration; thus considering only a force, the heavier the object is, it would accelerate faster. But an acceleration depends upon the two factors which are force and mass.
Newton's second law of motion states that the acceleration of an object is dependent upon the two factors which are, the net force of an object and the mass of the object.

3 0

3 years ago

A student is swimming south applying a force of 256 N. The water exerts a westward force of 104 N. If the student has a mass of

grigory [225]

Answer:

$a=2.9\ m/sec^2$

Explanation:

<u>Net Forces and Acceleration</u>

The second Newton's Law relates the net force $F_r$ acting on an object of mass m with the acceleration a it gets. Both the net force and the acceleration are vector and have the same direction because they are proportional to each other.

$\vec F_r=m\vec a$

According to the information given in the question, two forces are acting on the swimming student: One of 256 N pointing to the south and other to the west of 104 N. Since those forces are not aligned, we must add them like vectors as shown in the figure below.

The magnitude of the resulting force $F_r$ is computed as the hypotenuse of a right triangle

$|F_r|=\sqrt{256^2+104^2}$

$|F_r|=276.32\ Nw$

The acceleration can be obtained from the formula

$F_r=ma$

Note we are using only magnitudes here

$\displaystyle a=\frac{F_r}{m}$

$\displaystyle a=\frac{276.32Nw}{95.3Kg}$

$\boxed{a=2.9\ m/sec^2}$

7 0

3 years ago

A boat heads directly across a river. Its speed relative to the water is 3 m/s. It takes it 539 seconds to cross, but it ends up

nikklg [1K]

Answer:

3.24 m/s

Explanation:

Suppose that the boat sails with velocity (relative to water) direction being perpendicular to water stream. Had there been no water flow, it would have ended up 0m downstream

Therefore, the river speed is the one that push the boat 662 m downstream within 539 seconds. We can use this to calculate its magnitude

$v_r = 662 / 539 = 1.23 m/s$

So the boat velocity vector relative to the bank is the sum of of the boat velocity vector relative to the water and the water velocity vector relative to the bank. Since these 2 component vectors are perpendicular to each other, the magnitude of the total vector can be calculated using Pythagorean formula:

$v = \sqrt{v_b^2 + v_r^2} = \sqrt{3^2 + 1.23^2} = \sqrt{9 + 1.5129} = \sqrt{10.5129} = 3.24$ m/s

5 0

3 years ago

Which describes the ability to do work or to cause change?

Ierofanga [76]

Answer: Energy

Explanation: The ability to do work or cause change is called energy. Energy comes from many sources, and is found in two main forms. One form, potential energy, is energy that has the potential, in an object at rest, to do work later. An example of this would be a car parked at the top of a hill with its brakes on.

6 0

3 years ago

Read 2 more answers

A particular heat engine has a mechanical power output of 4.00 kW and an efficiency of 26.0%. The engine expels 8.55 103 J of ex

Ivahew [28]

To develop the problem we will start by finding the energy taken by each cycle through the efficiency of the motor and the exhausted energy. Later the work will be found for the conservation of energy in which this is equivalent to the difference between the two calculated energy values. Finally the estimated time will be calculated with the work and the power given,

$\text{Efficiency of the heat engine} = \eta = 26\% = 0.26$