Answer:
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Explanation:
Below is an attachment containing the solution.
Explanation:
It is given that,
Mass of the passenger, m = 75 kg
Acceleration of the rocket, 
(a) The horizontal component of the force the seat exerts against his body is given by using Newton's second law of motion as :
F = m a

F = 3675 N
Ratio, 

So, the ratio between the horizontal force and the weight is 5 : 1.
(b) The magnitude of total force the seat exerts against his body is F' i.e.


F' = 3747.7 N
The direction of force is calculated as :



Hence, this is the required solution.
Answer:
11.87
Explanation:
final velocity^2= initial velocity ^2+ 2* Acceleration* distance
Final Velocity^2= 9*9+2*1.5.20
final velocity^2 = 141
final velocity = 11.87
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