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Paladinen [302]
3 years ago
9

In a hospital setting, which of the following presents the possibility of being the source of an arc flash? A. Electrocautery De

vice B. Defibrillator C. Muscle Stimulation Electrodes D. Cauterization Tool
Physics
2 answers:
Umnica [9.8K]3 years ago
3 0
The answer to this question would be <span>Electrocautery Device

In a hospital, the device that can cause arc flash would be electrocautery device and circuit breaker. In fact, the electrocautery device uses the arc flash principle to work. The arc flash causing burns that surgeon use to clot bleeding in surgery or to destroy a tissue.</span>
Kamila [148]3 years ago
3 0

Answer:

B. Defibrillator

Explanation:

The electric arc occurs when there is a dielectric break in which it produces an electrical discharge. The term electric arc is the most common, but it can also be called an arc flash or short circuit as it is popularly called. This phenomenon is so strong that it can break the insulation made by air by conducting electrons from one electrode to another through a current flow.

A defibrillator is a device designed to discharge electrical charges to the chest wall (if external) or to the heart muscle fibers (if internal) of a patient with cardiac arrhythmia. Because of its ability to provide an electrical discharge, we can conclude that the defibrillator is a source of an electric arc in the hospital environment.

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Answer:

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To draw a diagram:

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5 0
2 years ago
A ball bearing of radius of 1.5 mm made of iron of density
Serjik [45]

Answer:

\boxed{\sf Viscosity \ of \ glycerine \ (\eta) = 14.382 \ poise}

Given:

Radius of ball bearing (r) = 1.5 mm = 0.15 cm

Density of iron (ρ) = 7.85 g/cm³

Density of glycerine (σ) = 1.25 g/cm³

Terminal velocity (v) = 2.25 cm/s

Acceleration due to gravity (g) = 980.6 cm/s²

To Find:

Viscosity of glycerine (\sf \eta)

Explanation:

\boxed{ \bold{v =  \frac{2}{9}  \frac{( {r}^{2} ( \rho -  \sigma)g)}{ \eta} }}

\sf \implies \eta =  \frac{2}{9}  \frac{( {r}^{2}( \rho -  \sigma)g )}{v}

Substituting values of r, ρ, σ, v & g in the equation:

\sf \implies \eta =  \frac{2}{9}  \frac{( {(0.15)}^{2}  \times  (7.85 - 1.25) \times 980.6)}{2.25}

\sf \implies \eta =  \frac{2}{9}  \frac{(0.0225 \times 6.6 \times 980.6)}{2.25}

\sf \implies \eta =  \frac{2}{9}  \times  \frac{145.6191}{2.25}

\sf \implies \eta =  \frac{2}{9}  \times 64.7196

\sf \implies \eta =  2 \times 7.191

\sf \implies \eta =  14.382 \: poise

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