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3 years ago

8

Cubes are three-dimensional square shapes that have equal sides. What is the density of a cube that has a mass of 12.6 g and a m

easured side length of 4.1 cm? (Density: D = m/v )

1 answer:

sweet-ann [11.9K]3 years ago

6 0

I got 3.07cm³. Its just 12.6 divided by 4.1

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Two coils are placed close together in a physics lab to demonstrate Faraday’s law of induction. A current of 5.00 A in one is sw

Mariana [72]

Answer:

Mutual inductance will be $M=1.8\times 10^{-3}Hennry$

Explanation:

We have given induced current $\Delta i=5A$

Time is given as $t=1ms=10^{-3}sec$

We have to find the mutual inductance between the coils

Induced emf is given as e = 9 volt

We know that induced emf is given by

$e=M\frac{\Delta i}{\Delta t}$

$9=M\times \frac{5}{10^{-3}}$

$M=1.8\times 10^{-3}Hennry$

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3 years ago

The projectile partially fills the end of the 0.3 m pipe. Calculate the force required to hold the projectile in position when t

zzz [600]

Answer:

Force is 7050N

Explanation:

See attached file

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3 years ago

Compared to its weight on Earth, a 5kg object on the moon will weigh

shutvik [7]

Answer:

8.1 N/49 N=0.1653 which means 16.53% of the weight of the object on Earth.

Explanation:

On the Moon, where the gravitational constant is 1.62 $\frac{m}{s^2}$ , the weight of the 5 kg object will be: $weight_M=m*g_M = 5 kg * 1.62 \frac{m}{s^2} =8.1 N$

Where the answer is in Newtons (N) since all quantities are given in the SI system.

On Earth, on the other hand, the weight of the object is:

$weight_E=m*g_E= 5 kg* 9.8 \frac{m}{s^2} = 49N$

Therefore the object's weight on the Moon compared to that on Earth will be:

$8.1N/49N=0.1653$

That is, 16.53% of the weight the object has on Earth.

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4 years ago

a 100 kg gymnast comes to a stop after tumbling. her feet do -5000J of net work to stop her. Use the work-kinetic energy theorem

VikaD [51]

W=ΔKE , W=-5000j
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6 0

3 years ago

Read 2 more answers

One of the checks that you could do for problem 1) would be to check the output resistance of the Wheatstone bridge to make sure

Ray Of Light [21]

Answer:

Explanation:

Let the four resistances of th wheat stone bridge is

P, Q, R and S and the value of each is 350 ohm.

Here, P and Q are in series.

R' = P + Q = 350 + 350 = 700 ohm

Then R and S are in series

R' = R + S = 350 + 350 = 700 ohm

Now R' and R'' are in parallel.

So, the equivalent resistance is

Req = R' x R'' / ( R' + R'')

Req = 700 / 2 = 350 ohm

Thus, the reading of ohmmeter is 350 ohm.

6 0

3 years ago