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3 years ago

IM DEAD PLS HELP ASAP

Mathematics

1 answer:

givi [52]3 years ago

5 0

Answer:

a. y = 0

b. x = 0

c. y = x

d. y = -x

Step-by-step explanation:

a. Since it is a horizontal line, its gradient does not change so its gradient shall remain as 0. Thus, y = 0x which is basically y = 0.

b. Since it is a vertical line, it is impossible to define its gradient or y-intercept but its x-intercept would always be at 0 so x = 0.

c. Since it is a line that is gradually getting higher across the x-axis, its gradient would be 1. It's y-intercept is 0 so the equation of this line would be y = 1x + 0, which is basically y = x. (We don't write 1x, but rather just x, putting zeros behind an equation is redundant)

d. Since it is a line that is gradually getting lower across the x-axis, its gradient would be -1. It's y-intercept is also 0 so the equation of this line would be y = -1x + 0, which is basically y = -x ((We don't write -1x, but rather just -x, putting zeros behind an equation is redundant)

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8.4.49 A cow is tethered to one corner of a square barn, 19 feet by 19 feet, with a rope 160 feet long. (See the illustration

SashulF [63]

Answer:

$20096 ft^2$

Step-by-step explanation:

We are given that

Length of rope=l=160 feet

Radius of quadrant of circle=r=160 feet

We have to find the maximum grazing area of the cow.

We know that

Area of quadrant of circle= $\frac{1}{4}\pi r^2$

Where $\pi=3.14$

Using the formula

Area grazed by cow= $\frac{1}{4}\times 3.14(160)^2$

Area grazed by cow= $20096 ft^2$

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3 years ago

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2 years ago

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ohaa [14]

Answer:

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Step-by-step explanation:

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3 years ago

A distribution of values is normal with a mean of 220 and a standard deviation of 13. From this distribution, you are drawing sa

Paraphin [41]

Answer:

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributied random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 220, \sigma = 13, n = 35, s = \frac{13}{\sqrt{35}} = 2.1974$

Find the interval containing the middle-most 48% of sample means:

50 - 48/2 = 26th percentile to 50 + 48/2 = 74th percentile. So

74th percentile

value of X when Z has a pvalue of 0.74. So X when Z = 0.643.

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$0.643 = \frac{X - 220}{2.1974}$

$X - 220 = 0.643*2.1974$

$X = 221.41$

26th percentile

Value of X when Z has a pvalue of 0.26. So X when Z = -0.643

$Z = \frac{X - \mu}{s}$

$-0.643 = \frac{X - 220}{2.1974}$

$X - 220 = -0.643*2.1974$

$X = 218.59$

The interval containing the middle-most 48% of sample means is between 218.59 to 221.41.

5 0

3 years ago

The graph of F(x) shown below resembles the graph of G(x) = x ^ 2 but it has been changed somewhat . Which of the following coul

Lorico [155]

Answer:

f(x) = 3 $x^{2}$ + 2

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one because I answered this question once in Brainly as well. Please have a look at the attached photo.

My answer:

Given G(x) = $x^{2}$

As we can see, the graph of f(x) is 2 units above the graphof g(x) in vertical (vertical shift)

=> f(x) = a $x^{2}$ + 2

As you can see, the graph of f(x) is stretched vertically by a dilation factor of 3 and there is no reflection, so a= 3

=> the equation of f(x) is: f(x) = 3 $x^{2}$ + 2

Hope it will find you well.

5 0

3 years ago