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2 years ago

Last year, the Humane Society found 96 homes for its stray kittens.

Mathematics

1 answer:

omeli [17]2 years ago

3 0

32 homes. divide 96 by 3 because the 96 homes each took 3 kittens

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Review

Ahat [919]

Answer: $\bold{a)\quad 51, 54, 57\qquad a_n=a_{n-1}+3}$

$\bold{b)\quad 250, 625, 1562.5\qquad a_n=(2.5)a_{n-1}}$

<u>Step-by-step explanation:</u>

a) This is an arithmetic sequence where 3 is added to the previous term.

48 + 3 = 51

51 + 3 = 54

54 + 3 = 57

The recursive formula for this sequence is: $a_n = a_{n-1}+3$

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b) This is a geometric sequence where 2.5 is multiplied to the previous term.

100(2.5) = 250

250 (2.5) = 625

625(2.5) = 1562.5

The recursive formula for this sequence is: $a_n=(2.5)a_{n-1}$

5 0

2 years ago

Answer the question in the picture above.

Anvisha [2.4K]

Answer:

m is less than A apparently

Step-by-step explanation:

3 0

3 years ago

On a scale drawing, a school is 1.6 feet tall. the scale factor is 1/22. Find the height of the school

Pie

Answer:

35.2 ft

Step-by-step explanation:

Multiply the scale factor and the height.

6 0

3 years ago

Read 2 more answers

An equation that represents the path of a diver jumping off a diving board is y = –7x2 + 5x + 16. Graph this function from the p

ANTONII [103]

Answer:

See explanation

Step-by-step explanation:

An equation that represents the path of a diver jumping off a diving board is

$y = -7x^2 + 5x + 16.$

The diver jumped to the water when x = 0.

Then

$y=-7\cdot 0^2+5\cdot 0+16=16$

The jumper reached the water when y = 0, then

$-7x^2+5x+16=0\\ \\D=5^2-4\cdot (-7)\cdot 16=25+448=473\\ \\x_{1,2}=\dfrac{-5\pm\sqrt{473}}{-14}$

So, point where the jumper reached the water is

$\left(\dfrac{5+\sqrt{473}}{14},0\right)\approx (1.93,0)$

7 0

3 years ago

Please help!! thank you.

Zina [86]

(A) Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ is:

$(-2x^{3}+x-5)(x^{3}-3x-4)$

$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$

$=(-2x^{3})(x^{3})+(-2x^{3})(-3x)+(-2x^{3})(-4)+x(x^{3})+(x)(-3x)+(x)(-4)+(-5)(x^{3})+(-5)(-3x)+(-5)(-4)$

$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$

$=-2x^{6}+6x^{4}+x^{4}+ 8x^{3}-5x^{3}-3x^{2}-4x+15x+20$

$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$

(B) Yes.

Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$ because multiplication is commutative.

Commutative Property of multiplication says that a.b = b.a.

Thus, multiplication is same irrespective of the order of two numbers.

5 0

3 years ago