Given :
On the first day of ticket sales the school sold 10 senior tickets and 1 child ticket for a total of $85 .
The school took in $75 on the second day by selling 5 senior citizens tickets and 7 child tickets.
To Find :
The price of a senior ticket and the price of a child ticket.
Solution :
Let, price of senior ticket and child ticket is x and y respectively.
Mathematical equation of condition 1 :
10x + y = 85 ...1)
Mathematical equation of condition 2 :
5x + 7y = 75 ...2)
Solving equation 1 and 2, we get :
2(2) - (1) :
2( 5x + 7y - 75 ) - ( 10x +y - 85 ) = 0
10x + 14y - 150 - 10x - y + 85 = 0
13y = 65
y = 5
10x - 5 = 85
x = 8
Therefore, price of a senior ticket and the price of a child ticket $8 and $5.
Hence, this is the required solution.
Answer:
3
Step-by-step explanation:
The difference between the length of arc BD and CE is 1.57 units
<h3>Length of an arc</h3>
length of arc = ∅ / 360 × 2πr
where
- r = radius
- ∅ = central angle
Therefore,
BD = 45 / 360 × 2 × 3.14 × 6 = 1695.6 / 360 = 4.71 units
CE = 45 / 360 × 2 × 3.14 × 8 = 2260.8 / 360 = 6.28 units
Therefore, the difference between the length of arc BD and CE is as follows:
6.28 - 4.71 = 1.57 units
learn more on length of arc here: brainly.com/question/3984590
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Answer:
x = y/ (Uk)
Step-by-step explanation:
U = y / xk
Multiply each side by xk
Uxk = y / xk *xk
U xk = y
Divide each side by Uk
U xk/ (Uk) = y/ (Uk)
x = y/ (Uk)
