Y=a(x-1)^2 -17 is the equation of the parabola.
at (0,16), 16=a(0-1)^2 -17. Solve for a = 33.
Equation is then y=33(x-1)^2-17 so when y=0,
(x-1)^2 = 17/33
x-1 = + and - square root of 17/33
x = 1.7177 and 0,2823 as the intercepts
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Answer: 2) 33.3
4) 31.9
6) 11
I hope this helped!
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- Zack Slocum
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Answer-
The exponential model best fits the data set.
Solution-
x = input variable = number of practice throws
y = output variable = number of free throws
Using Excel, Linear, Quadratic and Exponential regression model were generated.
The best fit equation and co-efficient of determination R² are as follows,
Linear Regression
Quadratic Regression
Exponential Regression
The value of co-efficient of determination R² ranges from 0 to 1, the more closer its value to 1 the better the regression model is.
Now,
Therefore, the Exponential Regression model must be followed.
Answer:
option no.D
6y+15x
Step-by-step explanation:
hope it helps
1.8x59 is 472
8(59)
2.9x84 is 756
9(84)
3.6x78 is 468
6(78)
4.7x96 is 672
7(96)