Answer:
2:1
1.2 × 10² g
Explanation:
Step 1: Write the balanced combustion equation
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to CH₄ is 2:1.
Step 3: Calculate the moles of CH₄ required to react with 15 moles of O₂
We will use the previously established molar ratio.
15 mol O₂ 1 mol CH₄/2 mol O₂ = 7.5 mol CH₄
Step 4: Calculate the mass corresponding to 7.5 moles of CH₄
The molar mass of CH₄ is 16.04 g/mol.
7.5 mol × 16.04 g/mol = 1.2 × 10² g
<span>As the moisture-rich air approaches the mountain, it rises and cools, and water molecules in the air combine to form small drops. The process where water vapor becomes a liquid is called condensation. </span>
Answer:
7.055 atm
Explanation:
T = (273 + 37)K = <em>310K</em>
The ideal gas constant =<em> 0.0821</em>atm.L/mol.K
Concentration = (0.90g)*(1mol/58.4g/0.100mL) = 0.154mol/L
Molar mass= Concentration*i
Osmotic pressure = Molar mass *the ideal gas constant*T
OP = (0.154)*(1.8)*(0.0821)*(310) = 7.055 atm
Magnesium plays a vital role in the function and structure of the body.
The adult human body consist of 25 grams of magnesium i.e. 0.25 % of the human body composition approximately.
Therefore, for a 60 kg adult, then the amount of magnesium in their body would be
= 0.15 kg
Convert kg to g:
1 kg = 1000 g
So, 0.15 kg = 
= 150 grams
Thus, amount of magnesium in 60 kg adult is equal to 150 grams
