Answer:
The answer to your question is A. 0.0066 moles or 6.6 x 10⁻³ moles
B. C₁₂H₂₂O₁₁ + 12 O₂ ⇒ 12 CO₂ + 11H₂O
Explanation:
A.
Data
mass of sugar water = 9 g
concentration = 25%
moles of sugar (C₁₂H₂₂O₁₁)
Formula
Mass percent = mass of solute/mass of solution x 100
-Solve for mass of solute
Mass of solute = (mass percent x mass of solution) / 100
-Substitution
Mass of solute = (25 x 9)/100
-Result
Mass of solute = 225/100
= 2.25 g of sugar
-Calculate the molar mass of sugar
C₁₂H₂₂O₁₁ = (12 x 12) + (22 x 1) + (11 x 16)
= 144 + 22 + 176
= 342 g
-Calculate the moles of sugar
342 g ---------------------- 1 mol
2.25 g ------------------- x
x = (2.25 x 1) / 342
x = 2.25/342
x = 0.0066 moles or 6.6 x 10⁻³ moles
B. Balanced chemical reaction
C₁₂H₂₂O₁₁ + 12 O₂ ⇒ 12 CO₂ + 11H₂O
