I'll solve for y
xy+(4(20))>x-5y(2+9-7)
xy+4(20)>x-5y(2+9-7)
xy+4(20)>x-5y(4)
xy+4(20)>x-20y
xy+80>x-20y
xy+20y+80>x
y(x+20)>-80+x
y>(-80+x)/(x+20)
Answer:
40 percent
Step-by-step explanation:
If you multiply 25x4 its 100, so 15x4 is 60 the rest would be 40. that 40 would be the rest of the percentage.
With the curve
parameterized by
with
, and given the vector field
the work done by
on a particle moving on along
is given by the line integral
where
The integral is then
Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
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