Which two numbers does √52 lie between on a number line?

Product of 3 and 25 plus the product of 5 and 30? It has to be an expression

Verdich [7]

3 x 25 + 5 x 30
hope this helps!!

6 0

4 years ago

A rectangle is 6 inches longer than it is wide. The perimeter of the rectangle is 44 inches.Write and solve an equation for the

Nataly_w [17]

Answer:

Length is 14 in

Width is 8 in

Step-by-step explanation:

Given:

Length = l
Width = w
Perimeter = P = 44 in

<h3>Solution</h3>

Equations as per given:

l - w = 6
P= 2(l+w) = 44 ⇒ l +w = 22

Adding up the two equations:

l - w + l +w = 6 + 22
2l = 28
l = 28/2
l = 14 in

Then finding the value of w:

w = l -6
w = 14 - 6
w = 8 in

Answer: The length of the rectangle is 14 inches and width is 8 inches

5 0

3 years ago

If a phone card is used to make a long distance phone call, you are charged $0.50 per call plus an additional $0.31 per minute.

Nikitich [7]

Part A: c for cost. c=0.31m+0.5

0.31m is the cost per minute. 0.5 is cost per call.

Part B: 0.31m+0.5=5.15 to solve we must rearrange.

subtract 0.5 from each side giving us 0.31m=4.85

divide by 0.31 giving us m=15.65

7 0

3 years ago

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

4 years ago

The square of a number added to 3 times the number is 28

Gre4nikov [31]

3x28=84

Step-by-step explanation:

7 0

4 years ago

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Which two numbers does √52 lie between on a number line? ​

Which two numbers does √52 lie between on a number line?