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victus00 [196]
3 years ago
6

What is the wall height for H??

Mathematics
2 answers:
Contact [7]3 years ago
7 0
<h2><u>To </u><u>find</u>:-</h2>

The height of the wall "h".

<h2><u>Solution</u>:-</h2>

{\boxed{\mathcal{\red{The\:height\:of\:the\:wall\:"h"\:is\:35.71\:ft.}}}}

<h2><u>Step</u>-<u>by</u>-<u>step</u> <u>explanation</u>:</h2>

\sf\purple{Using\:Pythagoras \:theorem, \:we\:have}

( {Perpendicular})^{2}  + ( {Base})^{2}  = ( {Hypotenuse})^{2}  \\ ➡ \:  {h}^{2}  +  ({35 \: ft})^{2}  =  ({50 \: ft})^{2}  \\ ➡ \:  {h}^{2}  + 1225 \:  {ft}^{2}  = 2500  \:  {ft}^{2} \\ ➡ \:  {h}^{2}  = 2500  {ft}^{2} - 1225  \:  {ft}^{2} \\ ➡ \:  {h}^{2}  = 1275  \:  {ft}^{2} \\ ➡ \: h \:  =  \sqrt{1275 \:  {ft}^{2} }  \\ ➡ \: h = 35.707\: ft \:  \\ ➡ \: h = 35.71\: ft

\sf\red{Therefore\:the\:height\:of\:the\:wall\:"h"\:is\:35.71\:ft.}

<h2><u>To</u> <u>verify</u> :-</h2>

( {35.71 \: ft})^{2}  + ( {35 \: ft})^{2}  =  ({50 \: ft})^{2}  \\ ✒ \: 1275 \:  {ft}^{2}  + 1225 \:  {ft}^{2}  \:  = 2500 \:  {ft}^{2}  \\ ✒ \: 2500 \:  {ft}^{2}  = 2500 \:  {ft}^{2}  \\ ✒ \: L.H.S.=R. H. S

Hence verified.

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

lesantik [10]3 years ago
3 0

Answer:

Step-by-step explanation:

Side "h" ( wall height ) is 35

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