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3 years ago

Plsss help asap edge

Mathematics

1 answer:

ki77a [65]3 years ago

3 0

Answer:

10 units

10000 units

10100101 units and 20 units

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Jason considered two similar televisions at a local electronics store. The generic version was based on the brand name and was t

Dafna11 [192]

Answer: Third option is correct.

Explanation:

Since we have given that

there are two similar televisions at a local electronics store,

<h3>Dimension of generic television set is </h3>

12 inches by 24 inches

We need to calculate the dimensions of brand name television ,

Since it is also given that the generic television was two third of the size of the brand name, i.e.

$\text{Generic television}=\frac{2}{3}\times \text{brand television}$

Now,

$\text{brand television }=\frac{3}{2}\times \text{generic television}$

So, length of brand name television becomes

$\frac{3}{2}\times 12=3\times 6=18\ inches$

Breadth of brand name television becomes

$\frac{3}{2}\times 24=3\times 12=36\ inches$

<h3>So, Dimension of brand name television is </h3>

18 inches by 36 inches

So, Third option is correct.

7 0

3 years ago

Read 2 more answers

Will give brainliest and thanks and please explain

Mumz [18]

Answer:

(65-5) / 2.5 = d

Step-by-step explanation:

100% sure

7 0

4 years ago

Read 2 more answers

Identify the equation that translates Y= In(X) five units down.

qwelly [4]

y = ln(x) - 5

For y = f(x),

y = f(x) + a

translates the function vertically by a units.

5 0

4 years ago

Read 2 more answers

1. Margo is selling boxes of nuts to raise money for her club. She finds that

Mamont248 [21]

Answer:

E none of the above

Step-by-step explanation:

4 0

3 years ago

The coordinates of trapezoid EFGH are E(4, 8), F(1, 2), G(6, 1), and H(8, 8). The image of EFGH under dilation is E'F'G'H'. If t

SSSSS [86.1K]

The image of EFGH under dilation is E'F'G'H'. If the coordnates of Vertex H' are (4,4), the coordinates of vertex E' are (2,4)

Second option (2,4)

Solution:

The point H has coordinates (8,8)

H=(8,8)=(xh,yh)→xh=8, yh=8

If the coordinates of vertex H' are (4,4)

H'=(4,4)=(xh',yh')→xh'=4, yh'=4

The factor of dilation "f" is:

f=xh'/xh=yh'/yh

f=4/8=4/8

f=4/8

Simplifying the fraction, dividing the numerator and denominator by 4:

f=(4/4)/(8/4)

f=1/2

Then we must multiply the original coordinates of EFGH by f=1/2 to obtain the new coordinates E'F'G'H'. Then, the coordinates of E' are:

E=(4,8)=(xe,ye)→xe=4, ye=8

xe'=f xe→xe'=(1/2) 4→xe'=4/2→xe'=2

ye'=f ye→ye'=(1/2) 8→ye'=8/2→ye'=4

E'=(xe',ye')→E'=(2,4)

6 0

4 years ago

Plsss help asap edge​

Plsss help asap edge