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Natasha_Volkova [10]
3 years ago
7

What is the least common denominator for the fractions below? 2/6 * 1/5

Mathematics
2 answers:
Vesna [10]3 years ago
7 0

Answer:

30

Step-by-step explanation:

Reika [66]3 years ago
6 0

Answer:

1/15

Step-by-step explanation:

2/6 x 1/5 = 2/30

2/30 = 1/15

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Guys help me please ,how to solve it? i need a solution
Ludmilka [50]

Answer:

well, x = 5

Step-by-step explanation:

here,

EB Is parallel to DC , so

Angle AEB = Angle ADE

( because they are corresponding angle pair )

Angle ABE = Angle ACD

( because they are corresponding angle pair )

triangle ADC Is similar to triangle AEB

(By AA similarity criteria )

hence AE / ED = AB / BC ( by CPCT )

so 24/10 = 12/x

=》 24/12= 10/x

=》 x = 5

okay i hope u got it

8 0
2 years ago
find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM​
Snezhnost [94]

\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}

  • Given - <u>A </u><u>trapezium</u><u> </u><u>ABCD </u><u>with </u><u>non </u><u>parallel </u><u>sides </u><u>of </u><u>measure </u><u>1</u><u>5</u><u> </u><u>cm </u><u>each </u><u>!</u><u> </u><u>along </u><u>,</u><u> </u><u>the </u><u>parallel </u><u>sides </u><u>are </u><u>of </u><u>measure </u><u>1</u><u>3</u><u> </u><u>cm </u><u>and </u><u>2</u><u>5</u><u> </u><u>cm</u>

  • To find - <u>Area </u><u>of </u><u>trapezium</u>

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

<u>Construction</u><u> </u><u>-</u>

draw \: CE \: \parallel \: AD \:  \\ and \: CD \: \perp \: AE

Now , we can clearly see that AECD is a parallelogram !

\therefore AE = CD = 13 cm

Now ,

AB = AE + BE \\\implies \: BE =AB -  AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm

Now , In ∆ BCE ,

semi \: perimeter \: (s) =  \frac{15 + 15 + 12}{2}  \\  \\ \implies \: s =  \frac{42}{2}  = 21 \: cm

Now , by Heron's formula

area \: of \: \triangle \: BCE =  \sqrt{s(s - a)(s - b)(s - c)}  \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)}  \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21}  \: cm {}^{2}

Also ,

area \: of \: \triangle \:  =  \frac{1}{2}  \times base \times height \\  \\\implies 18 \sqrt{21} =  \: \frac{1}{\cancel2}  \times \cancel12  \times height \\  \\ \implies \: 18 \sqrt{21}  = 6 \times height \\  \\ \implies \: height =  \frac{\cancel{18} \sqrt{21} }{ \cancel 6}  \\  \\ \implies \: height = 3 \sqrt{21}  \: cm {}^{2}

<u>Since </u><u>we've </u><u>obtained </u><u>the </u><u>height </u><u>now </u><u>,</u><u> </u><u>we </u><u>can </u><u>easily </u><u>find </u><u>out </u><u>the </u><u>area </u><u>of </u><u>trapezium </u><u>!</u>

Area \: of \: trapezium =  \frac{1}{2}  \times(sum \: of \:parallel \: sides) \times height \\  \\ \implies \:  \frac{1}{2}  \times (25 + 13) \times 3 \sqrt{21}  \\  \\ \implies \:  \frac{1}{\cancel2}  \times \cancel{38 }\times 3 \sqrt{21}  \\  \\ \implies \: 19 \times 3 \sqrt{21}  \: cm {}^{2}  \\  \\ \implies \: 57 \sqrt{21}  \: cm {}^{2}

hope helpful :D

6 0
2 years ago
10x^2+50 factoring by taking out the greatest common factor
inessss [21]

Answer:

The greatest common factor is 10

Step-by-step explanation:

Once you factor it out, you have :

10(x^2+5)

8 0
3 years ago
Integers are also known as....
Arada [10]

In short, the set formed by the negative integers, the number zero and the positive integers (or natural numbers) is called the set of integers. Integer is also known as a whole number.

5 0
3 years ago
Sam is a waiter at a local restaurant where he earns wages of $6 per hour. Sam figures that he also earns about $2.50 in tips fo
velikii [3]
C.

24 means that you earned 6 dollars an hour for 4 hours. 2.5n means that for every person, n, you receive an additional $2.50.
3 0
3 years ago
Read 2 more answers
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