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luda_lava [24]
3 years ago
8

Consider the energy diagram below.

Chemistry
1 answer:
nekit [7.7K]3 years ago
3 0

Answer:

alalalappapqpqpqpapa00apapapapap

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The orbital radii of four planets in our solar system is shown in the following table. Orbital Radii Planet Orbital Radii (AU) W
nalin [4]

Answer:

w and x

Explanation:

6 0
3 years ago
How many total orbitals are within the 3s, 3p, and<br> energy level?
Nina [5.8K]

The answer for the following question is explained below.

Therefore the total number of orbitals are " 9 ".

Explanation:

Orbital:

An orbital is a mathematical function that describes the wave-like behavior of an electron,electron pair,or the nucleons.

The total number of orbitals present in the 3rd energy level is 9.

Here,

A 3 s subshell has only one orbital.

A 3 p subshell has three orbitals.

A 3 d subshell has five orbitals.

Therefore the total number of orbitals is:

3 s = 1 orbital

3 p = 3 orbitals

3 d = 5 orbitals

total orbitals in 3rd energy level is = 1 + 3 + 5 =9

Therefore the total number of orbitals are " 9 ".

7 0
3 years ago
Read 2 more answers
Calculate the density a rectangular block of a metal whose length is 8.335cm width is 1.02cm height is 0.982cm and mass is 62.35
Ostrovityanka [42]

Answer:

Density rectangular block = 7.47 (Approx) gm/cm³

Explanation:

Given:

Length = 8.335 cm

Width = 1.02 cm

Height = 0.982 cm

Mass = 62.3538 gm

Find:

Density rectangular block

Computation:

Volume of block = lbh

Volume of block = (8.335)(1.02)(0.982)

Volume of block = 8.3486 cm³

Density = Mass / Volume

Density rectangular block = 62.3538 / 8.3486

Density rectangular block = 7.47 (Approx) gm/cm³

8 0
3 years ago
. If sulphur (IV) oxide and methane are
zubka84 [21]

Answer:

The answer is C. 1:2

Explanation:

5 0
3 years ago
96.0 g. of a gas occupies 48.0 L at 700.0 mm Hg and 20.0 °C. What is its molecular weight?
g100num [7]

Answer:

I hope this helps 52.2 g/mol

Explanation:

1) Solve for the moles using PV = nRT:

n = PV / RT

n = [(700.0 mmHg / 760.0 mmHg atm¯1) (48.0 L)] / [(0.08206 L atm mol¯1 K¯1) (293.0 K)]

n = 1.8388 mol

2) Divide the grams given (96.0) by the moles just calculated above:

96.0 g / 1.8388 mol = 52.2 g/mol

7 0
3 years ago
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